SQL多個結果不同的值

Question

我現在有一個類似的查詢到這一個..

select i.App_Id      as ApplicationId, 
     Cast(i.ObjectId as NVARCHAR(50)) as ObjectId, 
     1     as ActivityId, 
     Cast(case 
       when oh.ObjectId is null then 0 
       else 1 
       end as BIT)    as Highlight, 
     iu.UserId      as UserId 
    from table0 i 
     inner join table1 iu 
       on i.IdeaID = iu.IdeaID 
     left join table2 oh 
       on oh.ObjectId = i.IdeaID 
     left join table3 mIS 
       on i.IdeaID = mIS.IdeaID 
        AND mIS.EndTime is null 
     inner join table4 mISF 
       on mISF.StateFluxId = mIS.StateFluxId 
    where (iu.RelationId = 1 or iu.RelationId = 2) 

這是返回，例如：

2 | 1 | 1 | 1 | 1 
2 | 1 | 1 | 1 | 2 
2 | 1 | 1 | 1 | 3 

我m試圖改變它以合併第五列的結果，當其他列值相同時：

2 | 1 | 1 | 1 | 1,2,3 

這是pos錫布爾赫丁？沒有設法使用Stuff功能來完成它。

謝謝！

Answer 1

基於您的代碼我已經加入了XML PATH（）。請做根據您的要求

select i.App_Id      as ApplicationId, 
      Cast(i.ObjectId as NVARCHAR(50)) as ObjectId, 
      1     as ActivityId, 
      Cast(case 
        when oh.ObjectId is null then 0 
        else 1 
        end as BIT)    as Highlight, 
       stuff(
     (
     SELECT ',' + CAST(IU.USERID AS VARCHAR(10)) 
        FROM table1 t2 WHERE iu.IdeaID = t2.IdeaID 
            FOR XML PATH('') 
    ) 
               ,1,1,'') AS USERID 
     from table0 i 
      inner join table1 iu 
        on i.IdeaID = iu.IdeaID 
      left join table2 oh 
        on oh.ObjectId = i.IdeaID 
      left join table3 mIS 
        on i.IdeaID = mIS.IdeaID 
         AND mIS.EndTime is null 
      inner join table4 mISF 
        on mISF.StateFluxId = mIS.StateFluxId 
     where (iu.RelationId = 1 or iu.RelationId = 2) 
     GROUP BY i.App_Id 
       ,i.ObjectId, 
       oh.ObjectId 

Answer 2

你試過這樣的，

SELECT DISTINCT i.App_Id AS ApplicationId 
    ,Cast(i.ObjectId AS NVARCHAR(50)) AS ObjectId 
    ,1 AS ActivityId 
    ,Cast(CASE 
      WHEN oh.ObjectId IS NULL 
       THEN 0 
      ELSE 1 
      END AS BIT) AS Highlight 
    , 
    --iu.UserId      as UserId 
    (stuff(SELECT ',' + userid FROM table1 WHERE Ideaid = iu.IdeaId FOR XML path(''), 1, 1, '')) AS UserId 
FROM table0 i 
INNER JOIN table1 iu ON i.IdeaID = iu.IdeaID 
LEFT JOIN table2 oh ON oh.ObjectId = i.IdeaID 
LEFT JOIN table3 mIS ON i.IdeaID = mIS.IdeaID 
    AND mIS.EndTime IS NULL 
INNER JOIN table4 mISF ON mISF.StateFluxId = mIS.StateFluxId 
WHERE (
     iu.RelationId = 1 
     OR iu.RelationId = 2 
     )