Python：ipaddress.AddressValueError：至少需要3個部分

Question

ipaddress.IPv4Network的屬性可用於檢查是否保留了任何IP地址。

在IPython中：

In [52]: IPv4Address(u'169.254.255.1').is_private 
Out[52]: False 

然而，如果我嘗試同樣的事情在一個函數：

import ipaddress 
def isPrivateIp(ip): 
    unicoded = unicode(ip) 
    if ipaddress.IPv4Network(unicoded).is_private or ipaddress.IPv6Network(unicoded).is_private: 
     return True 
    else: 
     return False 

print isPrivateIp(r'169.254.255.1') 

我得到：

File "isPrivateIP.py", line 13, in <module> 
    print isPrivateIp(ur'169.254.255.1') 
    File "isPrivateIP.py", line 7, in isPrivateIp 
    if ipaddress.IPv4Network(unicoded).is_private or ipaddress.IPv6Network(unicoded).is_private: 
    File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/ipaddress.py", line 2119, in __init__ 
    self.network_address = IPv6Address(self._ip_int_from_string(addr[0])) 
    File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/ipaddress.py", line 1584, in _ip_int_from_string 
    raise AddressValueError(msg) 
ipaddress.AddressValueError: At least 3 parts expected in u'169.254.255.1' 

爲什麼會出現這種情況？

注意：在python 2中，ip地址必須作爲unicode對象傳遞給ipaddress函數，因此在字符串輸入ip上調用unicode()。

Answer 1

ipaddress.IPv6Network()的預期輸入與ipaddress.IPv4Network()不同。如果您從代碼中刪除or ipaddress.IPv6Network(unicoded).is_private，它可以正常工作。你可以從here瞭解更多。