因此,我一直在經常遇到這個問題,也許有人可以給我一個很好的解釋,說明如何或爲什麼不起作用。我想GROUP BY只是一列CSHFutureTAs.Time和香港專業教育學院試圖整合簡單的線條集體功能警告小組條款
GROUP BY CSHFutureTAs.Time
但是這給了我一個錯誤「試圖執行一個查詢,不包括指定表達式‘TA’作爲聚合函數的一部分「,任何人都可以幫助我?
完整的SQL(不帶GROUP CLAUSE):
SELECT CSHFutureTAs.TA
, CSHFutureTAs.TIME AS CSHGeneralTAs_TIME
, CSHFutureTAs.[CUT OFF TIME]
, CSHFutureTAs.SUNDAY AS CSHGeneralTAs_SUNDAY
, CSHFutureTAs.MONDAY AS CSHGeneralTAs_MONDAY
, CSHFutureTAs.TUESDAY AS CSHGeneralTAs_TUESDAY
, CSHFutureTAs.WEDNESDAY AS CSHGeneralTAs_WEDNESDAY
, CSHFutureTAs.THURSDAY AS CSHGeneralTAs_THURSDAY
, CSHFutureTAs.FRIDAY AS CSHGeneralTAs_FRIDAY
, CSHFutureTAs.SATURDAY AS CSHGeneralTAs_SATURDAY
, FUT_Totals.TIME AS GeneralTotals_Time
, FUT_Totals.SUNDAY AS GeneralTotals_SUNDAY
, FUT_Totals.MONDAY AS GeneralTotals_MONDAY
, FUT_Totals.TUESDAY AS GeneralTotals_TUESDAY
, FUT_Totals.WEDNESDAY AS GeneralTotals_WEDNESDAY
, FUT_Totals.THURSDAY AS GeneralTotals_THURSDAY
, FUT_Totals.FRIDAY AS GeneralTotals_FRIDAY
, FUT_Totals.SATURDAY AS GeneralTotals_SATURDAY
, CSHFutureTAs.[EXCEPTION DAYS]
, CSHFutureTAs.[EXCEPTION VALUE]
, IIf([FUT_Totals] ! [Time] = "09:00 - 21:00"
OR [FUT_Totals] ! [Time] = "10:00 - 22:00", 9, 1) AS SortKey
FROM
(
CSHFutureTAs
INNER JOIN FUT_Totals ON (CSHFutureTAs.[HG ID] = FUT_Totals.HG_ID)
AND (CSHFutureTAs.TIME = FUT_Totals.TIME)
)
INNER JOIN Current_INFO ON (CSHFutureTAs.[HG ID] = Current_INFO.[HG ID])
AND (CSHFutureTAs.[HEADER ID] = Current_INFO.[HEADER ID])
AND (FUT_Totals.HG_ID = Current_INFO.[HG ID])
ORDER BY IIf([FUT_Totals] ! [Time] = "09:00 - 21:00"
OR [FUT_Totals] ! [Time] = "10:00 - 22:00", 9, 1);
您必須使用GROUP BY或在select語句的每個字段(列)上使用聚合函數(Sum,Count,First等)。 – Fionnuala
請注意,作業標籤已被棄用,不應使用。 http://meta.stackexchange.com/questions/147100/the-homework-tag-is-now-officially-deprecated –
因此,沒有任何方式可以讓其餘的專欄保持中立,沒有總數或首先例如當我創建一個報告,我可以按時間分組,但它實際上工作,但它通過訪問嚮導。 – KSM