使用TSQL，如何在給定的術語之前和之後查找單詞和分組？

Question

給定一個特定的單詞模式（比如說「氣球」），我想查找前後的n個單詞的數量，按他們分組，計數存在於我的表格的標題中

對於，例如，如果數據集是：

• 紅氣球天空
• 黃色氣球的天空路
• 藍氣球椅

我想結果是這樣mething like：

- red balloon | 1 
- yellow balloon | 1 
- blue balloon | 1 
- balloon sky | 2 
- balloon chair | 1 

我覺得最好的方法來完成這將是在我的sproc正則表達式。因此，我添加了列出的極大正則表達式函數here和FindWordsInContext函數。

首先：

WITH Words_CTE (Title) 
AS 
-- Define the CTE query. 
(
    SELECT Title 
    FROM ItemData 
    WHERE Title LIKE '%balloon%' 
) 
-- Define the outer query referencing the CTE name. 
SELECT Title 
FROM Words_CTE 

所以我想我會開始與和工作FindWordsInContext功能混進去，然後做一個分組上的文字/給定字之前。

- 更新 -

得益於以下阿德里安Iftode ......但代碼不正是做什麼我要找的。

declare @table table(Sentence varchar(250)) 

insert into @table(sentence) 
    values ('I have another red balloon in the car.'), 
      ('Here is a new balloon for you.'), 
      ('A red balloon is in the other room.'), 
      ('Is there another balloon for me?') 


select TOP(5) SentencePart, NumberOfWords 
from @table 
cross apply dbo.fnGetPartsFromSentence(Sentence, 'balloon') f 
order by 
    NumberOfWords DESC, 
    case when f.Side = 'R' then 0 
    else 1 end 

輸出：

balloon is in the other room.  5 
I have another red balloon   4 
Here is a new balloon    4 
Is there another balloon   3 
balloon in the car.     3 

我希望能夠設置的「氣球」兩側的範圍內。在這種情況下，我們說一個字，輸出應該是：

red balloon  2 
new balloon  1 
another balloon 1 
balloon in  1 
balloon for  2 
balloon is  1 

Answer 1

是有點大量的代碼，我會盡力解釋

首先我用了一個分裂的功能，是要分裂一個varchar由給定的varchar

CREATE FUNCTION [dbo].[fnSplitString](@str NVARCHAR(MAX),@sep NVARCHAR(MAX)) 
RETURNS TABLE 
AS 
RETURN 
    WITH a AS(
     SELECT CAST(0 AS BIGINT) AS idx1, 
       CHARINDEX(@sep,@str) idx2, 
       1 as [Level] 
     UNION ALL 
     SELECT idx2 + coalesce(nullif(LEN(@sep),0),1), 
       CHARINDEX(@sep,@str, idx2 + 1), 
       [Level] + 1 as [Level] 
     FROM a 
     WHERE idx2 > 0 
    ) 
    SELECT SUBSTRING(@str,idx1,COALESCE(NULLIF(idx2,0),LEN(@str)+1)-idx1) AS Value, 
      [Level], 
      case when idx1 = 0 then 'R' when idx2 != 0 then 'LR' else 'L' end as Side 
    FROM a 

鑑於VARCHAR 「紅色氣球天空」並且當所述分裂是空格字符它將輸出：

select * 
from dbo.fnSplitString('red balloon sky', ' ') 

Value Level Side 
red  1  R 
balloon 2  LR 
sky  3  L 

Side部分表示：如果R表示空格在單詞的右側，如果L表示空格在單詞的左側，並且如果LR則單詞被空格包圍。

當分裂是「氣球」

select * 
from dbo.fnSplitString('red balloon sky', 'balloon') 

red  1 R 
sky 2 L 

所以氣球上的紅右側出現和天空

有了這個有用的功能的左側出現我創建了另一個函數，它將輸出單個句子所需的格式（varchar）

create FUNCTION [dbo].[fnGetPartsFromSentence](@sentence NVARCHAR(MAX),@word NVARCHAR(MAX)) 
RETURNS TABLE 
AS 
RETURN 


with RawData as 
(select rtrim(ltrim(f.Value)) as LR, 
     (select COUNT (*) from dbo.fnSplitString(rtrim(ltrim(f.Value)), ' ')) as NumberOfWords, 
     f.Side, 
     0 as SideLevel 
from dbo.fnSplitString(@sentence, @word) as f 
where f.Side = 'R' or f.Side = 'L' 
union all 
(
    select rtrim(ltrim(f.Value)) as LR, 
     (select COUNT (*) from dbo.fnSplitString(rtrim(ltrim(f.Value)), ' ')) as NumberOfWords, 
     f.Side, 
     sl.no as SideLevel 
    from dbo.fnSplitString(@sentence, @word) as f 
    join (select 1 as no union all select 2) sl on 1 = 1 
    where f.Side = 'LR' 
) 
) 
select (case when Side = 'R' then LR + ' ' + @word 
      when Side = 'L' then @word + ' ' + LR 
      when Side = 'LR' then 
        (
         case when SideLevel = 1 then @word + ' ' + LR 
         when SideLevel = 2 then LR + ' ' + @word 
         end 
        ) 
      end) as SentencePart, 
     (case when Side = 'R' or Side = 'L' then Side 
       else   
        ( case when SideLevel = 1 then 'L' 
         when SideLevel = 2 then 'R' 
         end 
        ) 
      end) as Side, 
     NumberOfWords   
from RawData 

此功能使用前一個。首先它將逐句分開，並通過再次按空格拆分來計算拆分中的單詞。當一個單詞出現在拆分的兩側時，它會重複拆分（加入1,2個值）。

該功能也將與字級聯，這取決於哪側輸出分割這是：左，右或兩者。它也會輸出Side，這次是Left或Right。

select * 
from [dbo].[fnGetPartsFromSentence]('yellow balloon sky road','balloon') 

SentencePart  Side NumberOfWords 

yellow balloon  R   1 
balloon sky road L   2 

現在使用此功能，我可以用交叉表應用它

declare @table table(Sentence varchar(250)) 

insert into @table(sentence) 
    values ('red balloon sky'), 
      ('yellow balloon sky road'), 
      ('blue balloon chair') 


select SentencePart, NumberOfWords 
from @table 
cross apply dbo.fnGetPartsFromSentence(Sentence, 'balloon') f 
order by 
    case when f.Side = 'R' then 0 
    else 1 end 

輸出是

red balloon   1 
yellow balloon  1 
blue balloon   1 
balloon chair   1 
balloon sky road  2 
balloon sky   1 

廠當有多次出現