PHP/SQL查詢中的Pivot/Cross選項卡結果

Question

在最新版本的WAMPserver下運行最新版本的PHP。

數據庫是SQL Server 2005

這是我正在運行的查詢的作品。我想要做的是改變從輸出：

CorrectionsCount , Employee , Date  
1    , Joe  , 02/12/2012 
31    , Barbara , 02/13/2012  
12    , Paula  , 02/16/2012 

要像這樣

[EMPLOYEE NAME], 02/12/2012, 02/13/2012, 02/16/2012  
Joe    , 31   , 0    , 0  
Barbara   , 0   , 31    , 0 
Paula   , 0   , 0    , 12 

代碼：

<?php 

// connect to DSN 
$DP2connect = odbc_connect("DB", "USER", "PWORD") or die ("Could not connect to 

server"); 

$DP2query = " 
SELECT SUM(CorrectionsCount),CorrectionUser, 
convert(char(10), DateHourCorrected, 120) 
FROM ISIImageCorrections 
WHERE DateHourCorrected BETWEEN '$theDate1' AND '$theDate2' 
GROUP BY CorrectionsCount,CorrectionUser,DateHourCorrected 
"; 


$DP2result2 = odbc_exec($DP2connect, $DP2query); 

odbc_result_all($DP2result2, 'id="results"'); 
?> 

$ thedate1和$ thedate2是變量被派駐到這個頁面通過另一個PHP頁面的日曆選擇器。

更新：我嘗試運行下面描述的COALESCE函數，但它在關鍵字'FROM'（在此語句中是「FROM」的第二個實例）附近生成語法錯誤。我輸入正確嗎？

$DP2connect = odbc_connect("dp2_database", "DP2", "DP2Express!") or die ("Could not connect to 

server"); 

$DP2query = 
"WITH T 
AS(
    SELECT CorrectionUser, CorrectionsCount, DateHourCorrected 
    FROM ISIImageCorrections 
) 
SELECT CorrectionUser, 
     COALESCE([02/12/2012], 0) AS [02/12/2012], 
     COALESCE([02/13/2012], 0) AS [02/13/2012], 
     COALESCE([02/16/2012], 0) AS [02/16/2012], 
FROM T 
PIVOT(SUM(CorrectionsCount) FOR [Date] IN([02/12/2012], [02/13/2012], [02/16/2012])) AS P"; 


$DP2result2 = odbc_exec($DP2connect, $DP2query); 

odbc_result_all($DP2result2, 'id="results"'); 

Answer 1

這裏我使用SUM，選擇你喜歡的任何聚合函數：

WITH T AS(
    SELECT Employee, CorrectionsCount, [Date] 
    FROM @yourTable 
) 
SELECT Employee, 
     COALESCE([02/12/2012], 0) AS [02/12/2012], 
     COALESCE([02/13/2012], 0) AS [02/13/2012], 
     COALESCE([02/16/2012], 0) AS [02/16/2012] 
FROM T 
PIVOT(SUM(CorrectionsCount) FOR [Date] 
     IN([02/12/2012], [02/13/2012], [02/16/2012])) AS P;