如何連接表，所以我得到的結果在一個表中

Question

客戶：

staffID | fname | lname 

inStorePay：

inStorePaymnet | hourlyPayment | staffId 

如何連接表，所以我得到的結果在一個表中？

Select hourlyPayment, (Count(hourlyPayment)* 100/(Select Count(*) From  
    inStorePay)) as rate 

    From inStorePay 

    Group By hourlyPayment 

    SELECT S.fname,S.lname, I.hourlyPayment 

    FROM Staff S, inStorePay I 

    WHERE S.staffID ='S0984' 

Answer 1

---

希望這個代碼可以幫助你

--Here Dbo.[InStorePay](StaffID) column depends on Dbo.[Customer](StaffID) ,Now you can join above tables Using StaffID column 
    CREATE TABLE [dbo].[Customer](
     StaffID INT IDENTITY, 
     Fname VARCHAR(200), 
     Lname VARCHAR(200) 
    PRIMARY KEY CLUSTERED 
    (
     [staffID] ASC 
    )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] 
    ) ON [PRIMARY] 

    GO 


    CREATE TABLE [dbo].[InStorePay](
     InStorePayId INT IDENTITY, 
     StaffID INT, 
     InStorePaymnet Money, 
     HourlyPayment Money 
    PRIMARY KEY CLUSTERED 
    (
     [InStorePayId] ASC 
    )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] 
    ) ON [PRIMARY] 

    GO 

    ALTER TABLE [InStorePay] ADD CONSTRAINT Fk_InStorePay_Customer FOREIGN Key (StaffID) REFERENCES Dbo.[Customer](StaffID) 

Answer 2

我希望這是你的要求是什麼

SELECT S.fname,S.lname, I.hourlyPayment,(Count(HourlyPayment)* 100/(Select Count(*) From 
#InStorePay)) as rate 
FROM #Customer S 
INNER JOIN #InStorePay I ON S.StaffID = I.StaffID 
WHERE S.staffID = 2 
Group By S.fname,S.lname, I.hourlyPayment 

以上查詢的結果會是這樣的