我想從可定義的日期範圍內的5個不同字段中搜索問題代碼,然後得到每個返回的問題代碼的總和。下面的「我的查詢」對每個查詢返回的每個問題代碼進行求和,但不會將一個查詢的總計添加到另一個查詢。訪問聯盟總和查詢
SELECT CUSTRAC.PROBLEM_CO, Count(CUSTRAC.PROBLEM_CO) AS CountOfPROBLEM_CO1
FROM CUSTRAC
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date]))
GROUP BY CUSTRAC.PROBLEM_CO, ([custrac].[problem_co])
HAVING (((CUSTRAC.PROBLEM_CO)<>""));
Union SELECT CUSTRAC.PROB_2, Count(CUSTRAC.PROB_2) AS CountOfPROB_2
FROM CUSTRAC
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date]))
GROUP BY CUSTRAC.PROB_2, ([custrac].[prob_2])
HAVING (((CUSTRAC.PROB_2)<>""));
Union SELECT CUSTRAC.PROB_3, Count(CUSTRAC.PROB_3) AS CountofPROB_3
FROM CUSTRAC
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date]))
GROUP BY CUSTRAC.PROB_3, ([custrac].[prob_3])
HAVING (((CUSTRAC.PROB_3)<>""));
Union SELECT CUSTRAC.PROB_4, Count(CUSTRAC.PROB_4) AS CountofPROB_4
FROM CUSTRAC
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date]))
GROUP BY CUSTRAC.PROB_4, ([custrac].[prob_4])
HAVING (((CUSTRAC.PROB_4)<>""));
UNION SELECT CUSTRAC.PROB_5, Count(CUSTRAC.PROB_5) AS CountofPROB_5
FROM CUSTRAC
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date]))
GROUP BY CUSTRAC.PROB_5, ([custrac].[prob_5])
HAVING (((CUSTRAC.PROB_5)<>""));
這還沒有有效的SQL。 UNION關鍵字不能是分號後的第一個標記。無論如何,你爲什麼使用UNION?這刪除重複。你想刪除重複?我猜不是。 –
我不認爲你使用'HAVING'的方式也是有效的。 「HAVING」應該與聚合函數一起使用。 –
我們還要提出這樣一個事實,即group by statement在所有五個查詢中提到了兩次相同的列。 –