爲什麼我的插入語句出現錯誤？

Question

我在我的insert語句中不斷收到有關我的逗號的錯誤。任何想法，爲什麼這可能是。

以下是錯誤消息：

消息102，級別15，狀態1，行3
附近有語法錯誤 ''。

和INSERT INTO...SELECT聲明

insert into custflag (cust_no, flag) 
    select 
     customer.cust_no 
    from 
     customer, dupaddr 
    where 
     customer.cust_no = dupaddr.cust_no, select cast(flag as int) 
              from flag 
              where flag_desc = 'Dup Customer' 

這裏是我的查詢的全部代碼。

SET IDENTITY_INSERT flag ON 
insert into flag (flag,flag_desc,available) 
values ((select Max(flag) from flag) + 1, 'Dup Customer', 1) 

create view dupaddr as 
select distinct c1.cust_no, c1.firstname, c1.lastname, c1.company, c1.predir + ' ' + c1.streetno + ' ' + c1.streetnm + ' ' + c1.suffix + ' ' + c1.postdir as fff ,c1.address2 
from customer c1,customer c2 
where c1.cust_no <> c2.cust_no 
and c1.firstname = c2.firstname 
and c1.lastname = c2.lastname 
and c1.company = c2.company 
and c1.predir + ' ' + c1.streetno + ' ' + c1.streetnm + ' ' + c1.suffix + ' ' + c1.postdir = c2.predir + ' ' + c2.streetno + ' ' + c2.streetnm + ' ' + c2.suffix + ' ' + c2.postdir 
and c1.address2 = c2.address2 



insert into custflag (cust_no,flag) 
select customer.cust_no from customer, dupaddr where customer.cust_no = dupaddr.cust_no , select cast(flag as int) from flag where flag_desc = 'Dup Customer' 

琢磨出來我加了標誌的觀點，並能簡化插入語句。謝謝你們每一個人的幫助！

SET IDENTITY_INSERT flag ON 
insert into flag (flag,flag_desc,available) 
values ((select Max(flag) from flag) + 1, 'Dup Customer', 1) 

create view dupaddr as 
select distinct c1.cust_no, 
c1.firstname, 
c1.lastname, 
c1.company, 
c1.predir + ' ' + c1.streetno + ' ' + c1.streetnm + ' ' + c1.suffix + ' ' + c1.postdir as fff , 
c1.address2, 
(SELECT cast(flag as int) FROM flag WHERE flag_desc = 'Dup Customer') as flag 
from customer c1,customer c2 
where c1.cust_no <> c2.cust_no 
and c1.firstname = c2.firstname 
and c1.lastname = c2.lastname 
and c1.company = c2.company 
and c1.predir + ' ' + c1.streetno + ' ' + c1.streetnm + ' ' + c1.suffix + ' ' + c1.postdir = c2.predir + ' ' + c2.streetno + ' ' + c2.streetnm + ' ' + c2.suffix + ' ' + c2.postdir 
and c1.address2 = c2.address2 



insert into custflag (cust_no,flag) 
select dupaddr.cust_no, dupaddr.flag from dupaddr 

Answer 1

爲了讓你查詢的工作，這裏是等效的代碼，

INSERT INTO custFlag(cust_no, flag) 
SELECT a.cust_no, c.flag 
FROM customer a 
     INNER JOIN dupaddr b 
      ON a.cust_no = b.cust_no 
     INNER JOIN 
     (
      SELECT cust_no, cast(flag as int) flag 
      FROM flag 
      WHERE flag_desc = 'Dup Customer' 
     ) c ON a.cust_no = c.cust_no 

但我懷疑CROSS JOIN是不是你想要的，你能告訴我怎麼表flag與customer相關和dupaddr？

Answer 2

正如我評論 - 不知何故你的代碼是一個有點混亂....目前尚不清楚這三個表customer，dupaddr和flag如何有關 - 他們應該得到適當的加入，讓你可以抓住cust_no和Flag從一個SELECT聲明。

我看不出Flag如何與其他表在所有 - 很坦率地說，我不明白爲什麼你甚至不需要dupaddr表在這裏都....

所以試一下像這樣：

insert into custflag (cust_no, flag) 
    select 
     customer.cust_no, 
     (select cast(flag as int) from flag where flag_desc = 'Dup Customer') 
    from 
     customer 
    inner join 
     dupaddr on customer.cust_no = dupaddr.cust_no -- why do you need this??? 

或自認爲flag似乎並沒有在所有被選擇要與任何行，你也可以你的語句之前抓住這個一次：

declare @flag INT 
select @flag = cast(flag as int) from flag where flag_desc = 'Dup Customer' 

insert into custflag (cust_no, flag) 
    select 
     customer.cust_no, @flag 
    from 
     customer 
    inner join 
     dupaddr on customer.cust_no = dupaddr.cust_no -- why do you need this??? 

Answer 3

你可以試試這個

insert into custflag (cust_no, flag) 
    select 
     customer.cust_no, (select cast(flag as int) 
              from flag 
              where flag_desc = 'Dup Customer') 
    from 
     customer, dupaddr 
    where 
     customer.cust_no = dupaddr.cust_no