如何在php中使用out \ n \ t \ r進行回顯？

Question

在我的代碼，這樣選擇：

<select name="TutorName"> 
     <?php 
     while ($tutor = mysql_fetch_array($resultTutor, MYSQL_ASSOC)) { 
     ?> 
     <option value="<?php echo $tutor['TutorPrefix'];?> 
         <?php echo $tutor['TutorFirstName'];?> 
         <?php echo $tutor['TutorLastName'];?>"> 
         <?php echo $tutor['TutorPrefix'];?> 
         <?php echo $tutor['TutorFirstName'];?> 
         <?php echo $tutor['TutorLastName'];?> </option> 

     <?php 
     } 
     ?> 
     </select> 

問題是，我得到這樣的結果在HTML

"TutorName":"Dr. \r\n\t\t\t\t\t\tSafaa \r\n\t\t\t\t\t\tNassar", 

我怎麼能加入他們在出\ r \ n \ t一行

我嘗試這一點，它不工作

<?php echo $tutor['TutorPrefix']$tutor['TutorFirstName']$tutor['TutorLastName'];?> 

Answer 1

<?php echo "$tutor[TutorPrefix]$tutor[TutorFirstName]$tutor[TutorLastName]";?> 

注意引號。

或者您也可以使用這種方法：

while ($tutor = mysql_fetch_array($resultTutor, MYSQL_ASSOC)) { 
    $input = "<option value='$tutor[TutorPrefix] 
        $tutor[TutorFirstName] 
        $tutor[TutorLastName]'> 
        $tutor[TutorPrefix] 
        $tutor[TutorFirstName] 
        $tutor[TutorLastName]' 
       </option>"; 
    //Do some processing according to the other answers 
    echo removeunwantedcharcters($input); 
} 

Answer 2

echo $tutor['TutorPrefix'].$tutor['TutorFirstName'].$tutor['TutorLastName']; 

Answer 3

與此

$output = str_replace(array("\r","\n","\t"), "", $input); 

嘗試也與此

$regex = '/(\s|\\\\[rntv]{1})/'; 
$output = preg_replace($regex, '', $input); 

Answer 4

嘗試你可以使用

$cleanString = trim($strname, "\t"); 

從字符串中刪除不需要的字符。

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