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我嘗試計算兩點之間的距離(給定以十進制格式表示這些點的緯度/經度)。訪問VBA:運行時錯誤'94':無效的空使用
VBA代碼:
Const pi = 3.14159265358979
Function distance(lat1, lon1, lat2, lon2)
Dim theta, dist
theta = lon1 - lon2
dist = Sin(deg2rad(lat1)) * Sin(deg2rad(lat2)) + Cos(deg2rad(lat1)) * Cos(deg2rad(lat2)) * Cos(deg2rad(theta))
dist = acos(dist)
dist = rad2deg(dist)
distance = (dist * 60 * 1.1515) * 1.609344
End Function
Function acos(rad)
If Abs(rad) <> 1 Then
acos = pi/2 - Atn(rad/Sqr(1 - rad * rad))
ElseIf rad = -1 Then
acos = pi
End If
End Function
Function deg2rad(deg)
deg2rad = CDbl(deg * pi/180)
End Function
Function rad2deg(rad)
rad2deg = CDbl(rad * 180/pi)
End Function
我也得到錯誤運行時錯誤 '94':在該線的無效使用Null 「deg2rad = CDbl(度* PI/180)」。 我寫了一個查詢:
SELECT DISTINCT
([band].E_laip+([band].E_min*(1/60))+([band].E_sec*(1/3600))) AS Band_E_dec,
([band2].E_laip+([band2].E_min*(1/60))+([band2].E_sec*(1/3600))) AS Band2_E_dec,
([band].N_laip+([band].N_min*(1/60))+([band].N_sec*(1/3600))) AS Band_N_dec,
([band2].N_laip+([band2].N_min*(1/60))+([band2].N_sec*(1/3600))) AS Band2_N_dec,
distance([Band_N_dec],[Band_E_dec],[Band2_N_dec],[Band2_E_dec]) AS Atstumas
FROM [band] LEFT JOIN band2 ON [band].Stotis = band2.Stotis;
也許有人有想法?提前致謝。