2017-04-15 105 views
0

我使用CRUD在線教程。不過,我已經到了更新部分,並且在GET函數和fetch_row方面遇到了一些問題。使用php和mysql更新

未定義的變量:fetched_row在C:\ XAMPP \ htdocs中\網站\ editsuppliers.php上線69是一個錯誤消息,並且接下來是未定義指數:editsuppliers

這是我到目前爲止所。

<?php 
include_once 'connect.php' ; 
if(isset($_GET['editsuppliers'])) 
{ 
$sql_query="SELECT * FROM suppliers WHERE SuppliersID=".$_GET['editsuppliers']; 
$result_set=mysql_query($sql_query); 
$fetched_row=mysql_fetch_array($result_set); 
} 
if(isset($_POST['btn-update'])) 
{ 
// variables for input data 
$SupplierID = $_POST['SupplierID']; 
$SupplierName = $_POST['SupplierName']; 
$Address = $_POST['Address']; 
$EmailAddress = $_POST['EmailAddress']; 
$PhoneNumber = $_POST['PhoneNumber']; 
    // variables for input data 

// sql query for update data into database 
$sql_query = "UPDATE suppliers SET SupplierID='$SupplierID',SupplierNamee='$SupplierName',Address='$Address',EmailAddress='$EmailAddress',PhoneNumber'$PhoneNumber' WHERE SupplierID=".$_GET['editsuppliers']; 
// sql query for update data into database 

// sql query execution function 
if(mysql_query($sql_query)) 
{ 
    ?> 
    <script type="text/javascript"> 
    alert('Data Updated Successfully'); 
    window.location.href='suppliers.php'; 
    </script> 
    <?php 
} 
else 
{ 
    ?> 
    <script type="text/javascript"> 
    alert('error occured while updating data'); 
    </script> 
    <?php 
} 
// sql query execution function 
} 
if(isset($_POST['btn-cancel'])) 
{ 
header("Location: suppliers.php"); 
} 
?> 

<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> 
<title>Edit Suppliers</title> 
<link rel="stylesheet" href="style.css" type="text/css" /> 
</head> 
<body> 
<center> 

<div id="header"> 
<div id="content"> 
    <label</label> 
    </div> 
</div> 

<div id="body"> 
<div id="content"> 
    <form method="post"> 
    <table align="center"> 
    <tr> 
    <td><input type="text" name="SupplierID" placeholder="Supplier ID" value="<?php echo $fetched_row['SupplierID']; ?>" required /></td> 
    </tr> 
    <tr> 
    <td><input type="text" name="SupplierName" placeholder="Supplier Name" value="<?php echo $fetched_row['SupplierName']; ?>" required /></td> 
    </tr> 
    <tr> 
    <td><input type="text" name="Address" placeholder="Address" value="<?php echo $fetched_row['Address']; ?>" required /></td> 
    </tr> 
    <tr> 
    <td><input type="text" name="EmailAddress" placeholder="Email Address" value="<?php echo $fetched_row['EmailAddress']; ?>" required /></td> 
    </tr> 
    <tr> 
    <td><input type="text" name="PhoneNumber" placeholder="Phone Number" value="<?php echo $fetched_row['PhoneNumber']; ?>" required /></td> 
    </tr> 
    <tr> 
    <td> 
    <button type="submit" name="btn-update"><strong>UPDATE</strong></button> 
    <button type="submit" name="btn-cancel"><strong>Cancel</strong></button> 
    </td> 
    </tr> 
    </table> 
    </form> 
    </div> 
</div> 

</center> 
</body> 
</html> 
+0

首先,因爲mysql_ *在PHP 5.5中被棄用(請參考[PHP doc](http://php.net/manual/en/function.mysql-connect.php)),你應該真的** **考慮使用[PPS:Prepared Parameterized Statements](http://php.net/manual/en/mysqli.quickstart.prepared-statements.php)。這將有助於[預防SQL注入](http://stackoverflow.com/questions/60174/how-can-i-prevent-sql-injection-in-php) – OldPadawan

+0

請使用'error_reporting(E_ALL); ini_set('display_errors',1);'在你的頁面頂部並且在你需要使用它們之前echo'$ _GET'和'$ _POST' vars,查看返回的內容(缺少其他東西?)我很漂亮確保'$ sql_query =「選擇*從供應商那裏供應商= =。$ _ GET ['editsuppliers'];'會讓你陷入麻煩...... – OldPadawan

+0

[Little Bobby](http://bobby-tables.com/)說[你的腳本處於SQL注入攻擊風險](http://stackoverflow.com/questions/60174/how-can-i-prevent-sql-injection-in-php)。瞭解[MySQLi](http://php.net/manual/en/mysqli.quickstart.prepared-statements.php)的[準備語句](http://en.wikipedia.org/wiki/Prepared_statement)。即使[轉義字符串](http://stackoverflow.com/questions/5741187/sql-injection-that-gets-around-mysql-real-escape-string)是不安全的。 – junkfoodjunkie

回答

0

根據你的陳述確保您傳遞的網址editsuppliers

請詳細解釋錯誤。

+0

中拋出一些關於它的事情我該怎麼做?關於fetched_row的錯誤出現在每個文本框中 –