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我有一個數據幀象下面這樣:簡單大熊貓透視表的問題
+-------+--------+----------+---------------+
| | ios_id | video_id | feed_position |
+-------+--------+----------+---------------+
| 11995 | user1 | 199 | 7 |
| 11996 | user2 | 164 | 18 |
| 11997 | user3 | 209 | 1 |
| 11998 | user3 | 85 | 4 |
| 11999 | user3 | 45 | 6 |
| 12000 | user3 | 150 | 10 |
| 12001 | user3 | 207 | 12 |
| 12002 | user3 | 203 | 26 |
| 12003 | user4 | 209 | 1 |
| 12004 | user4 | 202 | 1 |
| 12005 | user4 | 204 | 1 |
| 12006 | user4 | 126 | 2 |
| 12007 | user4 | 72 | 5 |
| 12008 | user4 | 108 | 10 |
| 12009 | user4 | 85 | 11 |
我想這樣做的是創建一個計算每個ios_id每個VIDEO_ID和feed_position的情況下,數據透視表。它應該是這樣的:
+------------+---+---+---+---+---+---+----+----+----+----+----+
| Row Labels | 1 | 2 | 4 | 5 | 6 | 7 | 10 | 11 | 12 | 18 | 26 |
+------------+---+---+---+---+---+---+----+----+----+----+----+
| 45 | | | | | 1 | | | | | | |
| 72 | | | | 1 | | | | | | | |
| 85 | | | 1 | | | | | 1 | | | |
| 108 | | | | | | | 1 | | | | |
| 126 | | 1 | | | | | | | | | |
| 150 | | | | | | | 1 | | | | |
| 164 | | | | | | | | | | 1 | |
| 199 | | | | | | 1 | | | | | |
| 202 | 1 | | | | | | | | | | |
| 203 | | | | | | | | | | | 1 |
| 204 | 1 | | | | | | | | | | |
| 207 | | | | | | | | | 1 | | |
| 209 | 2 | | | | | | | | | | |
+------------+---+---+---+---+---+---+----+----+----+----+----+
我想:
pd.pivot_table(df, values=['ios_id'],
index=['video_id'], columns=['video_id',
'feed_position'], aggfunc=np.count_nonzero)
但我遇到了這個錯誤:KeyError: 'Level video_id not found'
我如何能做到這一點有什麼想法?
'video_id'是'df'數據框中的一列嗎?看看你是不是混淆了數據框。此外,在使用'video_id'時,您可能會在列參數中使用索引變量接收到錯誤。 – Parfait