檢查整行是否存在

我想知道我的代碼有什麼問題..我正在嘗試將POST數據寫入我的數據庫但是在插入之前，檢查EQUAL行是否存在以及是否存在顯示的消息。我試了一下：檢查整行是否存在

這裏是我的querys在頁面的頂部：

if(isset($_POST['submitAddEvents'])){ 

    // Verify if the data exists 
    if(!filter_var($_POST['teamA'] && $_POST['teamB'] && $_POST['eventDate'])){ 
     $stmt = $db->prepare('SELECT * FROM events WHERE teamA = :teamA AND teamB = :teamB AND eventDate = :eventDate'); 
     $stmt->execute(array(
      ':teamA' => $_POST['teamA'], 
      ':teamB' => $_POST['teamB'], 
      ':eventDate' => $_POST['eventDate'], 
     )); 
     $row = $stmt->fetch(PDO::FETCH_ASSOC); 
    } 

    $statement = $db->prepare("INSERT INTO events(teamA, teamB, eventDate, `time`, live) VALUES (:teamA, :teamB, :eventDate, :timeOfEvent, :live)"); 
    $statement->execute(array(
     ':teamA' => $_POST['teamA'], 
     ':teamB' => $_POST['teamB'], 
     ':eventDate' => $_POST['date'], 
     ':timeOfEvent' => $_POST['timeOfEvent'], 
     ':live' => $_POST['live'], 
    )); 
    $id = $db->lastInsertId('ID'); 
} 
?>

這裏是我的腳本在頁面的底部：

<script> 
    //Saving Data 
    $('#saveButton').click(function(){ 
     var teamA = $('#teamA').val(); 
     var teamB = $('#teamB').val(); 
     var date = $('#date').val(); 
     var timeOfEvent = $('#timeOfEvent').val(); 
     var live = "0"; 
     if($("#live").is(':checked')) 
      live = $('#live').val(); 

     $.ajax({ 
      url : "<?= $_SERVER['PHP_SELF'] ?>", 
      type : "POST", 
      async: false, 
      data : 
      { 
       'submitAddEvents' : 1, 
       'teamA' : teamA, 
       'teamB' : teamB, 
       'date' : date, 
       'timeOfEvent' : timeOfEvent, 
       'live' : live, 
      }, 
      success:function(re) 
      { 
        window.location = "addEvents.php"; 
      } 
     }); 
    }); 
    </script>

但沒有工作，數據保存到數據庫中，並沒有通過任何驗證ajax提交...有人可以告訴我什麼是錯的嗎？有人可以幫我解決它嗎？

來源

2016-11-01 Rodrigo Pacheco

你會想從JavaScript發送數據到一個單獨的PHP頁面，然後'回聲json_encode（$ assocArray）'從PHP頁面，那麼你會得到響應，在你的對象'成功'方法的're'參數。 – PHPglue

如果你需要顯示ajax響應。你只是在服務器端迴應任何東西。你會在ajax成功提醒（重新）;像這 – JYoThI

你得到現有的行$row = $stmt->fetch(PDO::FETCH_ASSOC);，但你沒有做任何事情。使用if ($stmt->rowCount() == 0)檢查行計數是否爲零，然後執行代碼的其餘部分並插入數據。

來源

2016-11-01 05:01:18 Ergec

但我不想知道行數是零.. –

@RodrigoPacheco你的意思是「你不想」？它被禁止嗎？ – Ergec

如果您需要顯示服務器端的ajax響應。你只是在服務器端迴應任何東西。你會得到在阿賈克斯成功alert(re);這樣

阿賈克斯：

success:function(re) 
     { 
       alert(re); //here you get the message from server side 

       window.location = "addEvents.php"; 
     }

PHP：

在PHP中，你必須補充一點，如果條件檢查數據是否是重複或不像這樣

<?php 

    if(isset($_POST['submitAddEvents'])){ 

     // Verify if the data exists 
     if(!filter_var($_POST['teamA'] && $_POST['teamB'] && $_POST['eventDate'])){ 
      $stmt = $db->prepare('SELECT * FROM events WHERE teamA = :teamA AND teamB = :teamB AND eventDate = :eventDate'); 
      $stmt->execute(array(
       ':teamA' => $_POST['teamA'], 
       ':teamB' => $_POST['teamB'], 
       ':eventDate' => $_POST['eventDate'], 
      )); 
      $row = $stmt->fetch(PDO::FETCH_ASSOC); 

     if ($stmt->rowCount()==0) 
     { 



      $statement = $db->prepare("INSERT INTO events(teamA, teamB, eventDate, `time`, live) VALUES (:teamA, :teamB, :eventDate, :timeOfEvent, :live)"); 
      $statement->execute(array(
      ':teamA' => $_POST['teamA'], 
      ':teamB' => $_POST['teamB'], 
      ':eventDate' => $_POST['date'], 
      ':timeOfEvent' => $_POST['timeOfEvent'], 
      ':live' => $_POST['live'], 
      )); 
      $id = $db->lastInsertId('ID'); 

      echo "inserted succesfully "; 


     } 
     else 
     { 


      echo "not inserted because data duplicate"; 
     } 

     } 

    } 
    ?>

來源

2016-11-01 05:18:16 JYoThI

如果數據完全相同，它仍會添加我的數據而不顯示任何錯誤消息 –

PHP在一個單獨的頁面應該看起來更li柯：

<?php 
if(isset($_POST['submitAddEvents'])){ 
    // obviously these other things are also already set unless there's a hack 
    $tA = trim($_POST['teamA']); $tB = trim($_POST['teamA']); 
    $eD = trim($_POST['eventDate']); $tE = trim($_POST['timeOfEvent']); 
    $lV = trim($_POST['live']); 
    // Verify if the data exists 
    if($ta !== '' && $tB !== '' && $eD !== '' && $tE !== '' && $lV !== ''){ 
    // I like to save steps 
    $db->query("INSERT events (teamA, teamB, eventDate, `time`, live) VALUES ('$tA', '$tB', '$eD', '$tE', '$lV')"); 
    } 
    // doesn't look like you need to query the information you just entered - code above assumes STRING like data in MySQL, which may not be the case since we can't see your database 
} 
?>

來源

2016-11-01 05:25:00 PHPglue

檢查整行是否存在

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