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我有一個表單,當提交時,數據將被插入到三個表(用戶,旅程,user_journey表)中。在插入數據之前,我想檢查用戶表中是否已存在該用戶。如果沒有,那麼沒有問題,用戶將被插入到用戶表中,但是,如果用戶已經存在於用戶表中,我不想再次添加該用戶。我想獲取用戶的user_id並插入到第三個表(user_journey)中。檢查行是否存在
此刻,當我提交表單時,用戶即使已經存在於表中,也會插入到用戶表中。
我不確定我去檢查用戶是否存在正確以及如何獲取user_id的方式。任何意見,將不勝感激
$query = $db->query("SELECT COUNT(*) FROM user WHERE facebook_id = '.$hdnFacebookId.'");
//$query->execute();
//$countRows = $query->rowCount();//return number of rows
//check to see if user is already in the database
if ($query->fetchColumn() > 0)
{
if ($oneWay)
{
$query_journey = $db->prepare("INSERT INTO journey
(from_destination,to_destination,journey_type,depart_date,depart_time,seats_available,journey_message,user_type)
VALUES('$pjFrom','$pjTo','$radioJourneyType', STR_TO_DATE('$departDate','%d/%m/%Y'),'$newDepTime','$seatcounter','$textareanotes','$radUserType')");
}
else
{
$query_journey = $db->prepare("INSERT INTO journey
(from_destination,to_destination,journey_type,depart_date,depart_time,return_date,return_time,seats_available,journey_message,user_type)
VALUES('$pjFrom','$pjTo','$radioJourneyType', STR_TO_DATE('$departDate','%d/%m/%Y'),'$newDepTime',STR_TO_DATE('$returnDate','%d/%m/%Y'),'$newRetTime ','$seatcounter','$textareanotes','$radUserType')");
}
$user_query = $db->prepare("SELECT user_id FROM user WHERE facebook_id = '$hdnFacebookId'");
$result = $user_query->execute();
$user_query_result = $user_query->fetch(PDO::FETCH_ASSOC);
$query_journey->execute();//EXECUTE QUERY
$lastJourneyID = $db->lastInsertId();
$queryUserJourney = $db->prepare("INSERT INTO user_journey
(journey_id,user_id)
VALUES('$lastJourneyID','$user_query_result')");
$queryUserJourney->execute();//EXECUTE QUERY
//include('index.php');
}
else //insert user
{
//if $oneWay true, then omit $returnDate and $returnTime
if ($oneWay)
{
$query = $db->prepare("INSERT INTO journey
(from_destination,to_destination,journey_type,depart_date,depart_time,seats_available,journey_message,user_type)
VALUES('$pjFrom','$pjTo','$radioJourneyType', STR_TO_DATE('$departDate','%d/%m/%Y'),'$newDepTime','$seatcounter','$textareanotes','$radUserType')");
}
else
{
$query = $db->prepare("INSERT INTO journey
(from_destination,to_destination,journey_type,depart_date,depart_time,return_date,return_time,seats_available,journey_message,user_type)
VALUES('$pjFrom','$pjTo','$radioJourneyType', STR_TO_DATE('$departDate','%d/%m/%Y'),'$newDepTime',STR_TO_DATE('$returnDate','%d/%m/%Y'),'$newRetTime ','$seatcounter','$textareanotes','$radUserType')");
}
$queryfb = $db->prepare("INSERT INTO user
(facebook_id,facebook_username,facebook_first_name,facebook_last_name,facebook_image,facebook_link)
VALUES('$hdnFacebookId','$hdnUsername','$hdnFirstName','$hdnLastName','$hdnFacebookImg','$hdnFacebookUrl')");
$query->execute();
$lastUserID = $db->lastInsertId();
$queryfb->execute();
$lastJourneyID = $db->lastInsertId();
$queryUserJourney = $db->prepare("INSERT INTO user_journey
(user_id,journey_id)
VALUES('$lastJourneyID','$lastUserID')");
$queryUserJourney->execute();
}
修訂
function userExists($db, $hdnFacebookId)
{
$userQuery = "SELECT * FROM user WHERE facebook_id = :user;";
$stmt = $db->prepare($userQuery);
$stmt->execute(array(':user'=>$hdnFacebookId));
$result = $stmt->fetch(PDO::FETCH_ASSOC);
if($result)
{
return true;
}
return false;
}
$userExists = userExists($db,$hdnFacebookId);
if($userExists)
{
//don't insert user
//get user's id from database
$user_query = $db->prepare("SELECT * FROM user WHERE facebook_id = '$hdnFacebookId'");
$result = $user_query->execute();
$user_query_result = $user_query->fetch(PDO::FETCH_ASSOC);
$userID = $user_query_result['user_id'];
$query_journey->execute();//EXECUTE QUERY
$lastJourneyID = $db->lastInsertId();
$queryUserJourney = $db->prepare("INSERT INTO user_journey
(journey_id,user_id)
VALUES('$lastJourneyID','$userID')");
$queryUserJourney->execute();//EXECUTE QUERY
}
else
{
//insert user
}
或者更簡單地說,'return !! $ stmt-> fetch(PDO :: FETCH_ASSOC);' –
當然,它可以工作,我只是發現一些代碼比別人漂亮,但謝謝你的提示。即使它是一個關聯數組(它是),它也可以工作嗎? – Jonast92
它的工作方式與您發佈的代碼完全相同。 –