從窗體邊緣彈跳C＃

Question

我目前正在試圖讓3個球在窗體周圍彈跳，讓它工作，事情是我的代碼的這部分（使球從窗體的邊緣反彈）似乎很笨重，我覺得它可以以某種方式濃縮。在那裏，我可以清理

public void Move(int width, int height) 
     { 
      if ((position.X >= 0) && (position.X + size <= width)) //Within X Bounds 
      { 
       if (XBounce) 
       { 
        position.X -= speed; 
       } 
       else 
       { 
        position.X += speed; 
       } 
      } 
      else 
      { 
       if (!XBounce) 
       { 
        position.X -= size/2; 
       } 
       else 
       { 
        position.X += size/2; 
       } 
       XBounce = !XBounce; 
      } 

      if ((position.Y >= 0) && (position.Y + size <= height)) //Within Y Bounds 
      { 
       if (YBounce) 
       { 
        position.Y -= speed; 
       } 
       else 
       { 
        position.Y += speed; 
       } 
      } 
      else 
      { 
       if (!YBounce) 
       { 
        position.Y -= size/2; 
       } 
       else 
       { 
        position.Y += size/2; 
       } 
       YBounce = !YBounce; 
      } 

     } 

Answer 1

通過改變Xbounce和YBounce到int變量設置爲1或-1可以簡化事情有點辦法：

public void Move(int width, int height) 
    { 
     if ((position.X >= 0) && (position.X + size <= width)) //Within X Bounds 
     { 
      position.X -= XBounce * speed; 
     } 
     else 
     { 
      XBounce = -XBounce; 
      position.X -= XBounce * size/2; 
     } 

     if ((position.Y >= 0) && (position.Y + size <= height)) //Within Y Bounds 
     { 
       position.Y -= YBounce * speed; 
     } 
     else 
     { 
      YBounce = -YBounce; 
      position.Y -= YBounce * size/2; 
     } 
    }