2012-04-10 145 views
3

節點的位置。如果我有下面的圖,我設置節點的位置座標與矢量:如果我添加以下如何保持的igraph + R


library(igraph) 
library(Cairo) 

g9<- graph(c(0,1,0,2,0,3,1,4,1,2,3,4,3,5,4,5,5,2),n=6,dir=FALSE) 
V(g9)$name<-c(1:6) 
V(g9)$label<-V(g9)$name 
coords <- c(0, 0, 1.00000000000000, 0,0.500000000000000, 0.866025403784439, 0.300000000000000, 0.200000000000000, 0.441421356237309, 0.341421356237310,0.248236190979496,0.393185165257814) 
coords <- matrix(coords, 6,2,byrow=T) 
plot(g9,layout=coords) 

現在代碼,我必須重新設置座標佈局:


vc<-c(0,1,1,2,2,3,3,1) 
gp<-graph(vc,dir=FALSE); 
listSub<-graph.get.subisomorphisms.vf2(g9,gp) 

m<-matrix(c(unlist(listSub)),length(listSub),length(unique(vc)),byrow=T) 
md<-m[!duplicated(m[,1]),] 

g<-delete.vertices(g9,c(m[1,2])) 

dev.new() 

coord <- c(0, 0, 1.00000000000000, 0,0.500000000000000, 0.866025403784439, 0.441421356237309, 0.341421356237310,0.248236190979496,0.393185165257814) 
coord <- matrix(coord, 5,2,byrow=T) 
plot(g,layout=coord) 

如何使這些佈局位置成爲默認值 - 以便我可以對圖形的結構進行修改而不會丟失每個名稱的相應位置?


回答

1

你可以保持初始coord矩陣 ,只提取所需子行。

plot(g9, layout = coords[ V(g9)$name, ]) 
plot(g , layout = coords[ V(g)$name, ]) 
+0

非常感謝,它的工作原理! – user1310873 2012-04-10 09:28:51