2013-12-13 46 views

回答

8

使用/運算符。

echo '(4.2-1.3)/1' | bc 
9

1個工程確定劃分是否scale爲0(例如,如果你開始與BC和bc不改變scale),但如果失敗是scale陽性(例如,如果你開始與BC或bc -l增加scale )。 (見成績單下文)。對於一般的解決方案,使用trunc功能如下所示:
define trunc(x) { auto s; s=scale; scale=0; x=x/1; scale=s; return x }

成績單,說明1分頻本身如何在bc -l情況下會失敗,但如何trunc功能在向截斷工程確定零:

> bc -l 
bc 1.06.95 
[etc...] 
for (x=-4; x<4; x+=l(2)) { print x,"\t",x/1,"\n"} 
-4 -4.00000000000000000000 
-3.30685281944005469059 -3.30685281944005469059 
-2.61370563888010938118 -2.61370563888010938118 
-1.92055845832016407177 -1.92055845832016407177 
-1.22741127776021876236 -1.22741127776021876236 
-.53426409720027345295 -.53426409720027345295 
.15888308335967185646 .15888308335967185646 
.85203026391961716587 .85203026391961716587 
1.54517744447956247528 1.54517744447956247528 
2.23832462503950778469 2.23832462503950778469 
2.93147180559945309410 2.93147180559945309410 
3.62461898615939840351 3.62461898615939840351 
define trunc(x) { auto s; s=scale; scale=0; x=x/1; scale=s; return x } 
for (x=-4; x<4; x+=l(2)) { print x,"\t",trunc(x),"\n"} 
-4 -4 
-3.30685281944005469059 -3 
-2.61370563888010938118 -2 
-1.92055845832016407177 -1 
-1.22741127776021876236 -1 
-.53426409720027345295 0 
.15888308335967185646 0 
.85203026391961716587 0 
1.54517744447956247528 1 
2.23832462503950778469 2 
2.93147180559945309410 2 
3.62461898615939840351 3 
+0

感謝您的信息 –

+3

一個襯裏例:'BC <<< 「標度= 10; F =(55分之3);刻度= 0;(312 * F)/ 1」' –