爲什麼Python記錄異常到syslog

Question

的documentation爲Python 2.x的SysLogHandler的emit()功能說：

The record is formatted, and then sent to the syslog server. If exception information is present, it is not sent to the server.

...爲什麼？ source不是tell我多。我錯過了什麼？

然而，當我嘗試下面的代碼：

import logging 
from logging.handlers import SysLogHandler 

rootlogger = logging.getLogger() 
rootlogger.setLevel(logging.DEBUG) 
syslogh = SysLogHandler('/dev/log') 
rootlogger.addHandler(syslogh) 
# to see what's happening too 
consoleh = logging.StreamHandler() 
rootlogger.addHandler(consoleh) 

# this appears in the log 
rootlogger.info('foobar') 
try: 
    a = 42 
    a/0 
except ZeroDivisionError as e: 
    rootlogger.exception('myException!: {}'.format(e)) 

它編寫以下到syslog：

May 7 16:25:59 localhost foobar
May 7 16:25:54 localhost myException!: integer division or modulo by zero#012Traceback (most recent call last):#012 File "syslogonly.py", line 16, in #012 a/0#012ZeroDivisionError: integer division or modulo by zero

我使用rsyslog現在8.4.2在Debian喘息系統。

此外，我知道有多行的問題，但這是相關的嗎？

Answer 1

你不叫Logger.emit()。你打電話Logger.exception()，其中根據documentation，總是添加異常信息的消息：

Logs a message with level ERROR on this logger. The arguments are interpreted as for debug(), except that any passed exc_info is not inspected. Exception info is always added to the logging message. This method should only be called from an exception handler.

我沒有深入到源代碼，以確定什麼叫emit()，什麼情況下，但是。