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我有一個mysql函數將相應地更改記錄。但循環只執行一次,並留下循環與此條件。 「IF v_finished = 1 THEN LEAVE get_stock; END IF;」MYSQL循環在功能不能正常工作
但是它應該執行多次。就像在我的測試情況下,3次
BEGIN
DECLARE P_stock int(11);
DECLARE P_product int(11);
DECLARE V_From_warehouse int(11);
DECLARE V_To_warehouse int(11);
DECLARE v_finished INTEGER DEFAULT 0;
DECLARE V_To_warehouse_stock int(11);
DECLARE V_From_warehouse_stock int(11);
declare cur1 cursor for
SELECT material_transfer_details.product_id , material_transfer_details.quantity FROM
material_transfers,
material_transfer_details
WHERE
material_transfers.id = material_transfer_details.mtm_id
AND
material_transfers.status = 'Y'
AND
material_transfers.id = V_MTM_id;
DECLARE CONTINUE HANDLER
FOR NOT FOUND SET v_finished = 1;
SELECT warehouse_from INTO V_From_warehouse FROM material_transfers WHERE id =V_MTM_id;
SELECT warehouse_to INTO V_To_warehouse FROM material_transfers WHERE id =V_MTM_id;
OPEN cur1;
get_stock: LOOP
IF v_finished =1 THEN
LEAVE get_stock;
END IF;
fetch cur1 into P_product , P_stock;
SELECT quantity INTO V_To_warehouse_stock from stocks where warehouse_id = V_To_warehouse and product_id = P_product;
SELECT quantity INTO V_From_warehouse_stock from stocks where warehouse_id = V_From_warehouse and product_id = P_product;
IF (V_To_warehouse_stock IS NOT NULL)
THEN
UPDATE
stocks SET quantity = quantity - P_stock
WHERE
warehouse_id = V_to_warehouse
AND
product_id = P_product;
ELSE
INSERT INTO stocks(product_id , warehouse_id , quantity ,status, created_datetime , updated_datetime) values
(P_product , V_to_warehouse , 0-P_stock , 'Y', sysdate() , sysdate());
END IF;
IF (V_From_warehouse_stock IS NOT NULL)
THEN
UPDATE
stocks SET quantity = quantity + P_stock
WHERE
warehouse_id = V_from_warehouse
AND
product_id = P_product;
ELSE
INSERT INTO stocks(product_id , warehouse_id , quantity ,status, created_datetime , updated_datetime) values
(P_product , V_from_warehouse , P_stock , 'Y', sysdate() , sysdate());
END IF;
SET P_stock = 0;
SET P_product = 0;
END LOOP get_stock;
CLOSE cur1;
UPDATE material_transfers SET Status = 'N' WHERE id= V_MTM_id;
UPDATE material_transfer_details SET Status = 'N' WHERE mtm_id = V_MTM_id;
return '00000';
END
cur1有多少行,我的意思是選擇scrict返回任何行或不。首先檢查一次。 – Rams
它返回3行。我已經手動檢查過 –
「未找到的繼續處理程序」不僅會對光標起作用,而且還會在例如'SELECT warehouse_to INTO V_To_warehouse ...'沒有找到任何行 - 你顯然期望得到,因爲你在'IF(V_To_warehouse_stock IS NOT NULL)'中測試了這個行。您可以添加其他處理程序;您可以在獲取新行之前設置一個變量(這樣您可以在處理程序中檢查該變量);或其他類似的方式。 – Solarflare