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所以我有一些代碼,我正在爲一項任務編寫代碼,而且我一直在尋找來自3個浮點數的最小值和最大值。我目前得到的錯誤最小值和最大值C++
/usr/include/c++/4.9/bits/predefined_ops.h:121:39:錯誤:一元的「」無效的類型參數(有「浮」){ 返回布爾( _M_comp( __it1,* __ it2)); }
這是我當前的代碼:
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
//Name: Tanner Langan
//Student Number: 300224340
//Date: 2//16/2017
//Assignment 3
int main()
{
char c1;
float x1,x2,x3;
cout << "Please Enter 1 character and 3 float numbers. One at a time" << endl;
cout << "You must choose either X, N, V, or S for the character." << endl;
cout << "If you choose X the result displayed will be the the maximum of x1, x2, and x3" << endl;
cout << "If you choose N the result displayed will be the the minimum of x1, x2, and x3" << endl;
cout << "If you choose V the result displayed will be the the average of x1, x2, and x3" << endl;
cout << "If you choose S the program will terminate.";
cin >> c1;
cin >> x1;
cin >> x2;
cin >> x3;
while (c1 != 'S')
{
if(c1 == 'X' || c1 == 'x')
{
cout << "The max is" << std::max_element(x1,x2,x3) << endl;
main();
}
if(c1 == 'N' || c1 == 'n')
{
cout << "The min is" << std::min_element(x1,x2,x3) << endl;
main();
}
if(c1 == 'V' || c1 == 'v')
{
cout << "The average is" << (x1+x2+x3)/3 << endl;
main();
}
}
return 0;
}
你需要使用'std :: min'和'std :: max' – simpel01