Android的JSON請求 - JSON匹配異常

使用此功能，我的JSON數據到的對象讀取，然後嘗試打印其ID：Android的JSON請求 - JSON匹配異常

private void getJsonData(String url) { 
    StringBuilder builder = new StringBuilder(); 
    HttpClient client = new DefaultHttpClient(); 
    HttpGet httpGet = new HttpGet(url); 
    try { 
     HttpResponse response = client.execute(httpGet); 
     StatusLine statusLine = response.getStatusLine(); 
     int statusCode = statusLine.getStatusCode(); 
     if (statusCode == 200) { // success! 
      HttpEntity entity = response.getEntity(); 
      InputStream content = entity.getContent(); 
      BufferedReader reader = new BufferedReader(
        new InputStreamReader(content)); 
      String line; 
      while ((line = reader.readLine()) != null) { 
       builder.append(line); 
      } 
      JSONObject jsonObject = new JSONObject(builder.toString()); 
      for (int i = 0; i < jsonObject.length(); i++) { 
       Toast.makeText(context, jsonObject.getString("id"), Toast.LENGTH_LONG).show(); 
      } 
     } else { 
      Log.e(">>", "Failed to download file"); 
     } 
    } catch (ClientProtocolException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } catch (JSONException e) { 
     e.printStackTrace(); 
    } 
}

我得到這個錯誤：http://i.imgur.com/CkFOJmk.jpg

有任何想法嗎？在該行它的錯誤：

HttpEntity entity = response.getEntity();

我的PHP：

$this->db->select('id, unit_number'); 
    $this->db->from('parts'); 
    $this->db->order_by('unit_number', 'desc'); 
    $query = $this->db->get(); 
    echo json_encode($query->result());

來源

2013-03-28 user2011736

意味着ü沒有得到有效的JSON字符串形式的服務器PLZ其中U是從服務器獲取 –

@ρяσѕρєяK看起來好像我的JSON在最後因爲某些原因中旬對象獲得截止後充分反應。嗯.. – user2011736