sql LIKE子句中的錯誤在哪裏？

Question

我嘗試算這個選擇從另一個表中的所有項目：

SELECT id, name, (SELECT count(*) 
        FROM prekes_main 
        WHERE prekes_main.pristKaina = 1 
        and prekes_main.pg_kodas LIKE 'grupes_main.pg_kodas%') as pristKaina 
FROM grupes_main 
WHERE grupes_main.level = 1 
and grupes_main.name <> '' 

在LIKE子句中我想自動獲得選擇grupes_main列pg_kodas，但在此查詢總是返回0，哪裏是錯在LIKE功能？ thx

Answer 1

SELECT id, name, 
     (
     SELECT COUNT(*) 
     FROM prekes_main 
     WHERE prekes_main.pristKaina = 1 
       AND prekes_main.pg_kodas LIKE CONCAT(grupes_main.pg_kodas, '%') 
     ) pristKaina 
FROM grupes_main 
WHERE grupes_main.level = 1 
     AND grupes_main.name <> ''