CakePHP：hasMany association not recognized

Question

嘗試屬於用戶（用戶有很多嘗試）。

在user.php的（模型）

public $hasMany = array (
    'Attempt' => array(
     'className'  => 'Attempt', 
     'order' => 'modified DESC' 
    ), 
); 

在Attempt.php（模型）

public $belongsTo = array (
     'Test' => array ('className' => 'Test', 'foreignKey'=>'test_id', 'order' => 'Test.created DESC'), 
     'User' => array ('className' => 'User', 'order' => 'User.created DESC') 
    ); 

在控制器中，我們構建此查詢...

$joins = array(

     array( 
      'table'=>'attempts', 
      'alias'=>'Attempt', 
      'type'=>'LEFT', 
      'conditions'=>array("Attempt.user_id = User.id AND Attempt.test_id != {$practice_test_id}") 
     ) 

    ); 

$conditions[] = array('Resume.has_file = 1'); 

$search_options = array('conditions'=>$conditions, 
    //'joins' => $joins, //<--I'M FORCED TO USER THIS TO GET THIS TO WORK 
    'contain' => array('Resume', 'Attempt', 'Tag'), 
    'order' => array('Attempt.score'=> 'DESC'), 
    'group' => 'User.id' 
); 
$paginator_settings = $search_options; 
$paginator_settings['limit'] = 25; 
$this->Paginator->settings = $paginator_settings; 

$resume_display_array = $this->Paginator->paginate('User'); 

（這裏看起來有點奇怪，因爲我在這個查詢的構造之間剝去了很多分散注意力的邏輯，其中大多數c onditions是基於用戶輸入動態構建的。）

當我忽略了$search_options['joins]這不起作用。我得到以下錯誤：

Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Attempt.score' in 'order clause' 

的SQL轉儲看起來是這樣的：

SELECT `User`.`id` 
FROM `users` AS `User` 
LEFT JOIN `resumes` AS `Resume` ON (`Resume`.`user_id` = `User`.`id`) 
WHERE `User`.`id` IN (
    SELECT `User1`.`id` FROM `users` AS User1 
    LEFT JOIN `tags_users` AS TagUser ON (`User1`.`id`= `TagUser`.`user_id`) 
    LEFT JOIN `tags` AS Tag ON (`TagUser`.`tag_id`= `Tag`.`id`) 
    WHERE `Tag`.`id` = (2)) AND `Resume`.`has_file` = 1 GROUP BY `User`.`id` 
ORDER BY `Attempt`.`score` DESC 
LIMIT 25 

爲什麼沒有得到自動包含在嘗試模型由於與用戶的關係的hasMany？

Answer 1

我在這裏沒有看到問題。事實上，你今天發佈的other question不是你的答案嗎？

But this is not the case with hasMany and hasAndBelongsToMany associations. Here is where forcing joins comes to the rescue. You only have to define the necessary joins to combine tables and get the desired results for your query.

所以，從我的理解，你談論的是一個hasMany時強制聯接關係，對不對？這就是您在使用$joins陣列時所要做的。由於User hasMany Attempt，那麼你必須強制加入。現在，如果您從Attempt的角度進行分頁，那麼這可能不是必需的。如果您執行$this->Paginator->paginate('Attempt');（更改必要的關係和條件），則不需要手動加入用戶表以獲取數據。

因此，如果Attempt本身沒有加入（按照文檔所述），那麼訂單條件會產生問題，因爲在另一個查詢中檢索到Attempt數據，並且表引用在第一個查詢中丟失。解決方案：加入，蛋糕的行爲如預期。

Answer 2

我想你已經有了一個錯字在你的hasMany協會 - 的className有資本N.

我也想嘗試測試$this->User->recursive = 2; $this->User->find('first');，只是爲了看看它返回。如果結果不包括嘗試，我會假設你設置模型關係有什麼問題。

Answer 3

試試這個它會工作

$this->User->bindModel(array('hasMany' => array(
      'FollowUp' => array('className' => 'FollowUp', 'foreignKey' => 'publisher_id', 
      'fields' => array('amount'), 
     ), 
     'SchoolFollow' => array('className' => 'SchoolFollow', 'foreignKey' => 'publisher_id', 
      'fields' => array('amount'), 
     ), 
     'TravelerFollow' => array('className' => 'TravelerFollow', 'foreignKey' => 'publisher_id', 
      'fields' => array('amount'), 
     ), 
     $mdl . 'Cashback' => array('className' => $mdl . 'Cashback', 'foreignKey' => 'publisher_id', 
      'fields' => array('admin_comission_amount'), 
      'conditions' => array('status' => 'done') 
     ), 
)));