我正在使用SQL Server 2005,並且我的SQL查詢出現問題。基本上,我想根據所有客戶交易的最新日期,獲取由公司分組的所有客戶交易總額。SQL Server 2005 MAX,SUM和GROUP BY
的樣本數據:
Customer_Id Date Amount COMPANY
-------------------------------------------------
1 3/3/2014 9021 COMPANY X
2 3/3/2014 12000 COMPANY Y
2 3/15/2014 10000 COMPANY Y
2 3/30/2014 8000 COMPANY Y
4 3/13/2014 10000 COMPANY Z
5 3/14/2014 1400 COMPANY X
1 3/16/2014 2500 COMPANY X
7 3/14/2014 110 COMPANY Y
3 3/17/2014 1500 COMPANY Z
2 3/19/2014 2044 COMPANY Y
3 3/09/2014 9400 COMPANY Z
3 3/11/2014 8950 COMPANY Z
2 3/31/2014 3455 COMPANY Y
3 3/15/2014 950 COMPANY Z
6 3/15/2014 5543 COMPANY X
我想做到的是這樣的:
COMPANY TOTAL
COMPANY X 9443 --> sum from customer_id 1 (2500, as of 3/16/2014) and customer_id 6 (5542, 3/15/2014) and customer_id 5 (1400 as of 3/14/2014)
COMPANY Y 3455 --> sum from customer_id 2 (3455, as of 3/31/2014)
COMPANY Z 10950 --> sum from customer_id 4 (1000, as of 3/13/2014) and customer_id 3 (950, as of 3/15/2014)
下面是一些SQL查詢我試着不上我的目標而努力:
SELECT TOP (1) WITH TIES
Date, Company, SUM(Amount) AS total
FROM
tbl_Table
GROUP BY
Date, Company
ORDER BY
Date DESC
SELECT
t1.Date, t1.Company, SUM(t1.Amount) AS total
FROM
tbl_Table AS t1
INNER JOIN
(SELECT
MAX(Date) AS date, Company
FROM
tbl_Table
GROUP BY
Company) AS t2 ON t1.Date = t2.Date AND t1.Company = t2.Company
GROUP BY
t1.Date, t1.Company
WITH latest AS
(SELECT
Company, MAX(Date) AS maxdate
FROM
tbl_Table
GROUP BY
Company
)
SELECT
a.Date, a.Company, SUM(a.Amount) AS total
FROM
tbl_Table AS a
INNER JOIN
latest AS b ON a.Company = b.Company AND a.Date = b.maxdate
GROUP BY
a.Date, a.Company
謝謝,@Justin。你的解決方案解決了這一切雖然我現在不明白你的SQL代碼(即時新的SQL查詢),我會很快。再次感謝。關於「你的結果仍然不正確,你給的數據」,我忽略了這一點。抱歉。 – RedJohn