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看看這個Django的代碼:如何在django中編寫這個連接?
filtered = Question.objects.filter(children__marked=True).distinct()
return Question.objects.exclude(id__in=filtered)
它返回的所有問題的列表,除了那些有一個接受的(標記)的答案。我試圖讓它回覆問題以及upvoted的答案。看到這個SQL連接:
SELECT * from forum_node AS questions
JOIN forum_node AS answers
ON
questions.node_type = 'question' AND
answers.node_type = 'answer' AND
answers.parent_id = questions.id
WHERE
answers.score > 0 or answers.marked
現在,我怎麼翻譯這個連接到Django的?
幾乎 - 我實際上需要'Question.objects.exclude(id__in =(answers | upvoted))' – ripper234 2011-03-20 15:42:45