如何選擇與其對應的最早日期和數據

Question

我有一個非常簡單的問題，踢我的屁股。

CUSTNMBR | first_date | SOPNUMBE 
---------------------------------------- 
3344771005 | 2012-05-03 | 334471961748   
3344771005 | 2012-04-04 | 334476873726 

在上表我想回到與custnumbr和sopnumbe沿儘早所以它會看起來像這樣

3344771005 | 2012-04-04 | 334476873726 

我用這個

Select a.CUSTNMBR, min(a.Tax_Date) as first_date, a.SOPNUMBE 
from SOP30200 as a 
where a.CUSTNMBR = '3344771005' 
Group by a.CUSTNMBR, a.SOPNUMBE 

但返回所有變量，如果我敲掉組中的a.sopnumbe，則會出錯。

Answer 1

試試這個：

Select top 1 a.CUSTNMBR, a.Tax_Date as first_date, a.SOPNUMBE 
from SOP30200 as a 
where a.CUSTNMBR = '3344771005' 
order by a.Tax_Date asc 

Answer 2

嘗試

Select TOP 1 a.CUSTNMBR, min(a.Tax_Date)as first_date, a.SOPNUMBE 
from SOP30200 as a 
where a.CUSTNMBR = '3344771005' 
Group by a.CUSTNMBR, a.SOPNUMBE' 
ORDER BY 2 ASC