來自兩個表格的三列值之間的差異

Question

我有兩個文件，每列有三列。

data1.txt：https://pastebin.com/ezVr6KPi

# P (Gpa)  G/F. unit (a.u.)  T (K) 
-4.4119598462100 -941.5590019525371 10.0000000000000 
-4.4115664473800 -941.5589977004460 30.1000000000000 
-4.4084485632200 -941.5589688036446 50.2000000000000 
-4.3989188608700 -941.5588816009147 70.3000000000000 
... 

data2.txt：https://pastebin.com/veqBi8Er

# P (Gpa)  G/F. unit (a.u.)  T (K) 
7.5789845745700 -941.3858364185293 10.0000000000000 
7.5936983738200 -941.3856461092793 30.1000000000000 
7.6147899594200 -941.3853929461748 50.2000000000000 
7.6413267974900 -941.3851062350891 70.3000000000000 
... 

我已經在tables.sql腳本創建2個表，並命名爲列：

.headers on 

CREATE TABLE C_I("P1" TEXT, "G1" TEXT, "T1" TEXT); 
CREATE TABLE C_II("P2" TEXT, "G2" TEXT, "T2" TEXT); 

我導入數據：

.separator " " 

.import './data1.txt' C_I 
.import './data2.txt' C_II 

然後我從文件中刪除原始標題，只是指更好地上面給出的列名：G1T1

select T1 from C_I LIMIT 3; 
select P1 from C_I LIMIT 3; 
select G1 from C_I LIMIT 3; 

DELETE FROM C_I WHERE T1 == '(Gpa)'; 
DELETE FROM C_I WHERE P1 == '#'; 
DELETE FROM C_I WHERE G1 == 'P'; 

DELETE FROM C_II WHERE T2 == '(Gpa)'; 
DELETE FROM C_II WHERE P2 == '#'; 
DELETE FROM C_II WHERE G2 == 'P'; 

select * from C_I LIMIT 3; 
select * from C_II LIMIT 3; 

我想獲得的P1值，，， P2，G2，T2，其中：

P1 = P2（內的閾值）ANDT1 = T2（在閾值內）ANDG1 = G2（在閾值內）。

爲此，我做的事：

更新：

選項1：

SELECT * FROM C_I l1, C_II l2 
WHERE 
    ABS(l1.P1-l2.P2) < 0.005 
    AND 
    ABS(l1.T1-l2.T2) < 20.0 
    AND 
    ABS(l1.G1-l2.G2) < 0.005 

這將打印以下錯誤：

Error: incomplete SQL: SELECT * FROM C_I l1, C_II l2 
WHERE 
    ABS(l1.P1-l2.P2) < 0.005 
    AND 
    ABS(l1.T1-l2.T2) < 20.0 
    AND 
    ABS(l1.G1-l2.G2) < 0.005 

選項2：添加;

SELECT * FROM C_I l1, C_II l2; 
WHERE 
    ABS(l1.P1-l2.P2) < 0.005 
    AND 
    ABS(l1.T1-l2.T2) < 20.0 
    AND 
    ABS(l1.G1-l2.G2) < 0.005 

在這種情況下，整個的兩個表顯示通過終端， ，顯然此代碼已沒有作用。即使我在這三條語句中將閾值設置爲0.0，也會發生相同的情況（如果閾值爲0.0，則不會產生輸出）。

OPTION 3：作爲@Myonara建議，增加;這裏：

SELECT P, G, T FROM C_I l1 , C_II l2 
WHERE 
    ABS(l1.P1-l2.P2) < 0.005; 
    AND 
    ABS(l1.T1-l2.T2) < 20.0 
    AND 
    ABS(l1.G-l2.G2) < 0.005 

產生這個錯誤：

Error: incomplete SQL: AND 
    ABS(l1.T1-l2.T2) < 20.0 
    AND 
    ABS(l1.G1-l2.G2) < 0.005 

因此，這是我無法理解的是不工作

我希望你能幫助我。

完整的腳本：tables.sql：

我運行它爲：sqlite3 < tables.sql：

.headers on 

CREATE TABLE C_I("P1" TEXT, "G1" TEXT, "T1" TEXT); 
CREATE TABLE C_II("P2" TEXT, "G2" TEXT, "T2" TEXT); 

.separator " " 

.import './data1.txt' C_I 
.import './data2.txt' C_II 


select T1 from C_I LIMIT 3; 
select P1 from C_I LIMIT 3; 
select G1 from C_I LIMIT 3; 


DELETE FROM C_I WHERE T1 == '(Gpa)'; 
DELETE FROM C_I WHERE P1 == '#'; 
DELETE FROM C_I WHERE G1 == 'P'; 

DELETE FROM C_II WHERE T2 == '(Gpa)'; 
DELETE FROM C_II WHERE P2 == '#'; 
DELETE FROM C_II WHERE G2 == 'P'; 


select * from C_I LIMIT 3; 
select * from C_II LIMIT 3; 


SELECT * FROM C_I l1, C_II l2; 
WHERE 
    ABS(l1.P1-l2.P2) < 0.005 
    AND 
    ABS(l1.T1-l2.T2) < 20.0 
    AND 
    ABS(l1.G1-l2.G2) < 0.005 

Answer 1

試試這一個，因爲只有這個是完整的SQL語法SELECT，你需要：

SELECT P, G, T FROM C_I l1 , C_II l2 
WHERE 
    ABS(l1.P-l2.P) < 0.005 
    AND 
    ABS(l1.T-l2.T) < 20.0 
    AND 
    ABS(l1.G-l2.G) < 0.005; 

Answer 2

根據您的意見，這是適合您的腳本：

SELECT l1.p1, l2.p2, l1.t1, l2.t2, l1.g1, l2.g2 FROM C_I l1, C_II l2 WHERE ABS(l1.P1-l2.P2) < 0.005 AND ABS(l1.T1-l2.T2) < 20.0 AND ABS(l1.G1-l2.G2) < 0.005;

我會解釋這是什麼做的這個腳本： - 在這裏它只是創造一個笛卡爾乘積（也被稱爲交叉聯接），只要你想。這意味着它將提供一個具有680.000行（400行* 1700行= 680.000行）的表格，將提供for each record from table C_I1700 records from table C_II; 2.在WHERE條款它會做計算，並從腳本，你有only one (1) match所有your 3 conditions那裏; 3.例如，只有在這種情況下ABS(l1.P1-l2.P2) < 0.005你有91 matches，如果你應用第二個，那麼只有1匹配;

希望它能幫助你！