我想用我從3個點,其中計算的矢量繪製一個平面:如何在Matlab中繪製3D平面?
pointA = [0,0,0];
pointB = [-10,-20,10];
pointC = [10,20,10];
plane1 = cross(pointA-pointB, pointA-pointC)
如何在3D繪圖「基準面1」?
我想用我從3個點,其中計算的矢量繪製一個平面:如何在Matlab中繪製3D平面?
pointA = [0,0,0];
pointB = [-10,-20,10];
pointC = [10,20,10];
plane1 = cross(pointA-pointB, pointA-pointC)
如何在3D繪圖「基準面1」?
這裏的陰謀使用fill3
飛機一個簡單的方法:
points=[pointA' pointB' pointC']; % using the data given in the question
fill3(points(1,:),points(2,:),points(3,:),'r')
grid on
alpha(0.3)
'fill3'採取'X, Y,Z'作爲輸入而不是3分。看看你畫的飛機,它不會通過'(0,0,0)'。你畫了一個穿過'(0,-10,10)','(0,20,20)'和'(0,10,10)' –
的平面根據Matlab文檔(fill3的第二行)「 fill3(X,Y,Z,C)填充三維多邊形,X,Y和Z三元組指定多邊形頂點「。儘管我輸入點數爲'fill3'(使用了錯誤的維數),但我做了一個錯誤,現在已經糾正了。感謝您的注意。我仍然認爲一個班輪比幾條線更好...... – bla
沒關係,無論如何你都有我的upvote,我只是想讓你糾正這個錯誤:) –
您已經計算出的法向量。現在你應該決定你的飛機在x
和z
的限制,並創建一個矩形的補丁。
解釋:每個平面可用其法向量(A,B,C)
和另一個係數D
來表徵。這架飛機的方程式是AX+BY+CZ+D=0
。跨產品之間兩點之間的差異,cross(P3-P1,P2-P1)
允許查找(A,B,C)
。爲了找到D
,簡單地把任何一點到上面提到的公式:
D = -Ax-By-Cz;
一旦你有平面的方程,你可以坐4分擺在這個平面上,並得出他們之間的補丁。
normal = cross(pointA-pointB, pointA-pointC); %# Calculate plane normal
%# Transform points to x,y,z
x = [pointA(1) pointB(1) pointC(1)];
y = [pointA(2) pointB(2) pointC(2)];
z = [pointA(3) pointB(3) pointC(3)];
%Find all coefficients of plane equation
A = normal(1); B = normal(2); C = normal(3);
D = -dot(normal,pointA);
%Decide on a suitable showing range
xLim = [min(x) max(x)];
zLim = [min(z) max(z)];
[X,Z] = meshgrid(xLim,zLim);
Y = (A * X + C * Z + D)/ (-B);
reOrder = [1 2 4 3];
figure();patch(X(reOrder),Y(reOrder),Z(reOrder),'b');
grid on;
alpha(0.3);
這就是我想出了:
function [x, y, z] = plane_surf(normal, dist, size)
normal = normal/norm(normal);
center = normal * dist;
tangents = null(normal') * size;
res(1,1,:) = center + tangents * [-1;-1];
res(1,2,:) = center + tangents * [-1;1];
res(2,2,:) = center + tangents * [1;1];
res(2,1,:) = center + tangents * [1;-1];
x = squeeze(res(:,:,1));
y = squeeze(res(:,:,2));
z = squeeze(res(:,:,3));
end
,你會爲使用:
normal = cross(pointA-pointB, pointA-pointC);
dist = dot(normal, pointA)
[x, y, z] = plane_surf(normal, dist, 30);
surf(x, y, z);
其中在飛機上繪製邊長爲60的正方形問題
我想補充一下Andrey Rubshtein給出的答案,他的代碼在B = 0時非常好用。這裏是他的代碼編輯後的版本
下面的代碼的工作原理當不爲0
normal = cross(pointA-pointB, pointA-pointC);
x = [pointA(1) pointB(1) pointC(1)];
y = [pointA(2) pointB(2) pointC(2)];
z = [pointA(3) pointB(3) pointC(3)];
A = normal(1); B = normal(2); C = normal(3);
D = -dot(normal,pointA);
zLim = [min(z) max(z)];
yLim = [min(y) max(y)];
[Y,Z] = meshgrid(yLim,zLim);
X = (C * Z + B * Y + D)/ (-A);
reOrder = [1 2 4 3];
figure();patch(X(reOrder),Y(reOrder),Z(reOrder),'r');
grid on;
alpha(0.3);
下面的代碼工作時,C不是0
normal = cross(pointA-pointB, pointA-pointC);
x = [pointA(1) pointB(1) pointC(1)];
y = [pointA(2) pointB(2) pointC(2)];
z = [pointA(3) pointB(3) pointC(3)];
A = normal(1); B = normal(2); C = normal(3);
D = -dot(normal,pointA);
xLim = [min(x) max(x)];
yLim = [min(y) max(y)];
[Y,X] = meshgrid(yLim,xLim);
Z = (A * X + B * Y + D)/ (-C);
reOrder = [1 2 4 3];
figure();patch(X(reOrder),Y(reOrder),Z(reOrder),'r');
grid on;
alpha(0.3);
你爲什麼使用reOrder? @奎師那切塔尼亞 –
我相信有SE網站matlab。 –
nope,我的錯誤 - > http://area51.stackexchange.com/proposals/38040/matlab –
你很可能需要生成一堆點在飛機上,然後繪製那些使用「衝浪」或一些類似的功能... – Isaac