我怎樣才能使用從同一個表中兩個不對稱行之間的時間差?DATEDIFF
select
[endtime]
,[realtime]
from [prin]
where ([realtime] is not null) and ([endtime] is not null and)
order by [realtime]
between end date time and next start date time
我怎樣才能使用從同一個表中兩個不對稱行之間的時間差?DATEDIFF
select
[endtime]
,[realtime]
from [prin]
where ([realtime] is not null) and ([endtime] is not null and)
order by [realtime]
between end date time and next start date time
使用DateDiff
函數來獲取兩個日期之間的差異。 添加day
參數來獲取天的差別。
SELECT
[endtime]
,[realtime]
,datediff (day,[endtime],lead ([realtime]) over (order by [realtime])) as days_endtime_2_next_realtime
FROM [prin]
WHERE ([realtime] is not null)
AND ([endtime] is not null)
ORDER BY [realtime]
一樣。沒有解釋代碼的作用? –
@ AT-2016,請隨時進行編輯,並將其添加到答案 –
@ F.Kahalaj,附:如果你喜歡你可能想要讚揚的答案 –
create table #a
(
date_1 date,
date_2 date
)
insert into #a values
('1-10-16','2-10-16'),
('2-10-16','3-10-16'),
('3-10-16','4-10-16')
;with cte as
(
select
date_1,date_2
,lead(date_2,1) over (order by date_2) as lead_value
from #a
where (date_1 is not null) and (date_2 is not null)
)
select date_1,date_2,
datediff(Day,date_1,lead_value) as diffrence from cte
你的問題還不是很清楚,圖像沒有幫助。將問題中的樣本數據*和*想要的結果與期望的結果一起放入。 –
憑什麼你想這樣做?不清楚。 –