DATEDIFF

Question

我使用datediff得到兩個日期時間之間的差異四捨五入到最接近的30分鐘：此

DATEDIFF(hh, CAST(CAST(dbo.QuickLabDump.[Date Entered] AS DATE) AS DATETIME) 
    + CAST(dbo.QuickLabDump.[Time Entered] AS TIME), 
    CAST(CAST(dbo.QuickLabDump.[Date Completed] AS DATE) AS DATETIME) 
    + CAST(dbo.QuickLabDump.[Time Completed] AS TIME)) AS [Hours TurnAround] 

我不明白，我從這句話得到的行爲，但我需要的是什麼，是>= :30, round up, if not, round down,

問題如何在30分鐘內完成下舍入，如果大於或等於30分鐘，可以將小時數累加起來？

Answer 1

您應該計算在幾分鐘內DATEDIFF，做一個ROUND則：

ROUND(CAST(DATEDIFF(MINUTES, CAST(CAST(dbo.QuickLabDump.[Date Entered] AS DATE) AS DATETIME) 
         + CAST(dbo.QuickLabDump.[Time Entered] AS TIME), CAST(CAST(dbo.QuickLabDump.[Date Completed] AS DATE) AS DATETIME) 
         + CAST(dbo.QuickLabDump.[Time Completed] AS TIME)) AS FLOAT)/60,0) AS [Hours TurnAround]