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我試圖從類數據插入到數據庫playframework JPA.em（）。merge（this）; SQLGrammarException
這裏我的模型類
package models;
import java.util.*;
import javax.persistence.*;
import javax.persistence.Entity;
import javax.validation.*;
import play.data.validation.Constraints;
import play.data.validation.Constraints.*;
import play.api.db.*;
import play.db.jpa.*;
import javax.persistence.EntityManager;
@Entity
public class MedicalIncident {
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
public int id;
@Constraints.Required
public String month;
@Constraints.Required
public String place;
@Constraints.Required
public String unit;
@Constraints.Required
public String incident_type;
@Constraints.Required
public int age;
/**
* Insert this new incident submission.
*/
public void toDataBase() {
// persist object - add to entity manager
JPA.em().merge(this);
JPA.em().persist(this);
}
}
.merge方法給我的錯誤：
[info] play - Application started (Dev)
[error] o.h.e.j.s.SqlExceptionHelper - Kolumna "MEDICALINC0_._EBEAN_INTERCEPT" nie istnieje
Column "MEDICALINC0_._EBEAN_INTERCEPT" not found; SQL statement:
select medicalinc0_.id as id1_0_0_, medicalinc0_._ebean_intercept as _ebean_i2_0_0_, medicalinc0_.age as age3_0_0_, medicalinc0_.incident_type as incident4_0_0_, medicalinc0_.month as month5_0_0_, medicalinc0_.place as place6_0_0_, medicalinc0_.unit as unit7_0_0_ from MedicalIncident medicalinc0_ where medicalinc0_.id=? [42122-172]
[error] play - Cannot invoke the action, eventually got an error: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not prepare statement
[error] application -
! @6ghb8od3o - Internal server error, for (POST) [/incydent_medyczny/zapisz] ->
play.api.Application$$anon$1: Execution exception[[PersistenceException: org.hibernate.exception.SQLGrammarException: could not prepare statement]]
at play.api.Application$class.handleError(Application.scala:293) ~[play_2.10.jar:2.2.1]
at play.api.DefaultApplication.handleError(Application.scala:399) [play_2.10.jar:2.2.1]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
at scala.Option.map(Option.scala:145) [scala-library.jar:na]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2.applyOrElse(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
Caused by: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not prepare statement
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1387) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1310) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1316) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.merge(AbstractEntityManagerImpl.java:898) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at models.MedicalIncident.toDataBase(MedicalIncident.java:43) ~[na:na]
at controllers.MedicalIncidents.submit(MedicalIncidents.java:50) ~[na:na]
Caused by: org.hibernate.exception.SQLGrammarException: could not prepare statement
at org.hibernate.exception.internal.SQLStateConversionDelegate.convert(SQLStateConversionDelegate.java:123) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.engine.jdbc.internal.StatementPreparerImpl$StatementPreparationTemplate.prepareStatement(StatementPreparerImpl.java:188) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.engine.jdbc.internal.StatementPreparerImpl.prepareQueryStatement(StatementPreparerImpl.java:159) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1859) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
Caused by: org.h2.jdbc.JdbcSQLException: Kolumna "MEDICALINC0_._EBEAN_INTERCEPT" nie istnieje
Column "MEDICALINC0_._EBEAN_INTERCEPT" not found; SQL statement:
select medicalinc0_.id as id1_0_0_, medicalinc0_._ebean_intercept as _ebean_i2_0_0_, medicalinc0_.age as age3_0_0_, medicalinc0_.incident_type as incident4_0_0_, medicalinc0_.month as month5_0_0_, medicalinc0_.place as place6_0_0_, medicalinc0_.unit as unit7_0_0_ from MedicalIncident medicalinc0_ where medicalinc0_.id=? [42122-172]
at org.h2.message.DbException.getJdbcSQLException(DbException.java:329) ~[h2.jar:1.3.172]
at org.h2.message.DbException.get(DbException.java:169) ~[h2.jar:1.3.172]
at org.h2.message.DbException.get(DbException.java:146) ~[h2.jar:1.3.172]
at org.h2.expression.ExpressionColumn.optimize(ExpressionColumn.java:144) ~[h2.jar:1.3.172]
at org.h2.expression.Alias.optimize(Alias.java:52) ~[h2.jar:1.3.172]
at org.h2.command.dml.Select.prepare(Select.java:808) ~[h2.jar:1.3.172]
所有我可以看到它讓我發現，列「MEDICALINC0 _._ EBEAN_INTERCEPT」找不到，這是非常明顯的原因，我真的dosnt在db中有該列。 我的DB：
create table MedicalIncident (
id bigint not null,
month varchar(255),
place varchar(255),
unit varchar(255),
incident_type varchar(255),
age bigint,
constraint pk_MedicalIncident primary key (id))
;
或者我應該使用persist（）方法？
我沒有conf/application.conf中的任何ebean條目 – masterdany88
檢查我更新的答案。 –
有沒有在ebean build.sbt – masterdany88