目前我正在學習Linux上的POSIX線程。以下示例計算整數數組中有多少個3(int),它在CentOS 6.5上返回正確答案,但在macOS 10.12.4上返回錯誤答案。pthread互斥鎖在macOS上無法正常工作
#include <stdlib.h>
#include <semaphore.h>
#include <pthread.h>
#include <unistd.h>
#include <stdio.h>
#define thread_num 16
#define MB 1024 * 1024
int *array;
int length; //array length
int count;
int t; //number of thread
void *count3s_thread(void* id);
pthread_mutex_t myMutex;//create a mutex
int main()
{
//initialize mutex
if (pthread_mutex_init(&myMutex, NULL) != 0)
printf("Mutex init failed!\n");
int i;
int tid[thread_num];
pthread_t threads[thread_num];
length = 64 * MB;
array = malloc(length * 4);
//initialize the array
//when i is an odd number, array[i] = 4
//when i is an even number, array[i] = 3
for (i = 0; i < length; i++)
array[i] = i % 2 ? 4 : 3;
for (t = 0; t < thread_num; t++)
{
count = 0;
tid[t]=t;
int err = pthread_create(&(threads[t]), NULL, count3s_thread,&(tid[t]));
if (err)
{
printf("create thread error!\n");
return 0;
}
}
for (t = 1; t < thread_num; t++)
pthread_join(threads[t], NULL);
printf("Total count= %d \n",count);
pthread_mutex_destroy(&myMutex);
return 0;
}
void *count3s_thread(void* id)
{
//printf("id from count3s_thread = %d\n", *(int *)id);
int length_per_thread = length/thread_num; //length of every thread
int start = *(int *)id * length_per_thread;
int i;
for (i = start; i < start + length_per_thread; i++)
{
if (array[i] == 3)
{
pthread_mutex_lock(&myMutex);
count++;
pthread_mutex_unlock(&myMutex);
}
}
return NULL;
}
答案應該是64 * 1024 * 1024/2 = 67,108,864/2 = 33,554,432。但是macOS上的答案是不對的。我編譯下列選項代碼:
gcc mutex-demo.c -lpthread -o mutex-demo
我試圖解決這個問題下面this link。但是,我仍然得到了初始化pthread互斥鎖的錯誤答案。我錯過了什麼?
PS:我試過pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;
或pthread_mutex_init(&mutex, NULL)
,但運行在macOS上的程序仍然返回錯誤答案。
高級謝謝!
pthread_join的'for'循環從'1'開始,而不是'0'。 – mch
如果您在沒有'pthread_create'的情況下調用函數,您是否得到了正確的值?我沒有得到您的預期價值:http://ideone.com/z3Ne2a – mch