2014-01-23 124 views
-1

以下變量是通過拉普拉斯變換求解ODE系統的解。問題是,我如何評估這是t的功能?從拉普拉斯評估求解

zs = 

(426453367703541750000*sin(t))/422998807223231216101 - (126885219268500000*cos(t))/422998807223231216101 - (143127622539985885236418500000*sum(exp(r3*t)/(2*(169386*r3^3 + 3312090*r3^2 + 336237395*r3 + 891000000)), r3 in RootOf(s3^4 + (736020*s3^3)/28231 + (336237395*s3^2)/84693 + (594000000*s3)/28231 + 13810500000/28231, s3)))/422998807223231216101 - (898981813790513658018000000*sum((r3*exp(r3*t))/(2*(169386*r3^3 + 3312090*r3^2 + 336237395*r3 + 891000000)), r3 in RootOf(s3^4 + (736020*s3^3)/28231 + (336237395*s3^2)/84693 + (594000000*s3)/28231 + 13810500000/28231, s3)))/422998807223231216101 - (35837444893658057322750000*sum((r3^2*exp(r3*t))/(2*(169386*r3^3 + 3312090*r3^2 + 336237395*r3 + 891000000)), r3 in RootOf(s3^4 + (736020*s3^3)/28231 + (336237395*s3^2)/84693 + (594000000*s3)/28231 + 13810500000/28231, s3)))/422998807223231216101 + (10746289875507070500000*sum((r3^3*exp(r3*t))/(2*(169386*r3^3 + 3312090*r3^2 + 336237395*r3 + 891000000)), r3 in RootOf(s3^4 + (736020*s3^3)/28231 + (336237395*s3^2)/84693 + (594000000*s3)/28231 + 13810500000/28231, s3)))/422998807223231216101 


zu = 

(423526351592241700000*sin(t))/422998807223231216101 - (119538342000000*cos(t))/422998807223231216101 - (21856954524657863661418500000*sum(exp(r3*t)/(2*(169386*r3^3 + 3312090*r3^2 + 336237395*r3 + 891000000)), r3 in RootOf(s3^4 + (736020*s3^3)/28231 + (336237395*s3^2)/84693 + (594000000*s3)/28231 + 13810500000/28231, s3)))/422998807223231216101 - (935131412760109308018000000*sum((r3*exp(r3*t))/(2*(169386*r3^3 + 3312090*r3^2 + 336237395*r3 + 891000000)), r3 in RootOf(s3^4 + (736020*s3^3)/28231 + (336237395*s3^2)/84693 + (594000000*s3)/28231 + 13810500000/28231, s3)))/422998807223231216101 - (35869453347570289778100000*sum((r3^2*exp(r3*t))/(2*(169386*r3^3 + 3312090*r3^2 + 336237395*r3 + 891000000)), r3 in RootOf(s3^4 + (736020*s3^3)/28231 + (336237395*s3^2)/84693 + (594000000*s3)/28231 + 13810500000/28231, s3)))/422998807223231216101 + (10124060799006000000*sum((r3^3*exp(r3*t))/(2*(169386*r3^3 + 3312090*r3^2 + 336237395*r3 + 891000000)), r3 in RootOf(s3^4 + (736020*s3^3)/28231 + (336237395*s3^2)/84693 + (594000000*s3)/28231 + 13810500000/28231, s3)))/422998807223231216101 

回答

0

這些是用符號數學工具箱構建的嗎?

嘗試

t=0:0.01:10; 
values_s = zs(t); 
values_u = zu(t); 
+0

他們是象徵性的。 – user3227891

+0

你是否嘗試過?它有用嗎? 我不確定我明白你到底想要做什麼... – scenia