C++從遊戲客戶端解密msg

我做了一個接受遊戲連接的套接字，在遊戲中你應該輸入用戶名和密碼，我可以收回它bt，我的問題是在哪裏看，所以我可以理解如何處理這個概率，是否有一個tut。或提示或somthing，我可以工作，所以我可以達到什麼是尋找!?C++從遊戲客戶端解密msg

感謝。

unsigned char* Key3; 
unsigned char* Key4; 
unsigned char Low; 
unsigned char High; 

const unsigned char Key1[] = 
{ 
    0x9D, 0x90, 0x83, 0x8A, 0xD1, 0x8C, 0xE7, 0xF6, 0x25, 0x28, 0xEB, 0x82, 0x99, 0x64, 0x8F, 0x2E, 
    0x2D, 0x40, 0xD3, 0xFA, 0xE1, 0xBC, 0xB7, 0xE6, 0xB5, 0xD8, 0x3B, 0xF2, 0xA9, 0x94, 0x5F, 0x1E, 
    0xBD, 0xF0, 0x23, 0x6A, 0xF1, 0xEC, 0x87, 0xD6, 0x45, 0x88, 0x8B, 0x62, 0xB9, 0xC4, 0x2F, 0x0E, 
    0x4D, 0xA0, 0x73, 0xDA, 0x01, 0x1C, 0x57, 0xC6, 0xD5, 0x38, 0xDB, 0xD2, 0xC9, 0xF4, 0xFF, 0xFE, 
    0xDD, 0x50, 0xC3, 0x4A, 0x11, 0x4C, 0x27, 0xB6, 0x65, 0xE8, 0x2B, 0x42, 0xD9, 0x24, 0xCF, 0xEE, 
    0x6D, 0x00, 0x13, 0xBA, 0x21, 0x7C, 0xF7, 0xA6, 0xF5, 0x98, 0x7B, 0xB2, 0xE9, 0x54, 0x9F, 0xDE, 
    0xFD, 0xB0, 0x63, 0x2A, 0x31, 0xAC, 0xC7, 0x96, 0x85, 0x48, 0xCB, 0x22, 0xF9, 0x84, 0x6F, 0xCE, 
    0x8D, 0x60, 0xB3, 0x9A, 0x41, 0xDC, 0x97, 0x86, 0x15, 0xF8, 0x1B, 0x92, 0x09, 0xB4, 0x3F, 0xBE, 
    0x1D, 0x10, 0x03, 0x0A, 0x51, 0x0C, 0x67, 0x76, 0xA5, 0xA8, 0x6B, 0x02, 0x19, 0xE4, 0x0F, 0xAE, 
    0xAD, 0xC0, 0x53, 0x7A, 0x61, 0x3C, 0x37, 0x66, 0x35, 0x58, 0xBB, 0x72, 0x29, 0x14, 0xDF, 0x9E, 
    0x3D, 0x70, 0xA3, 0xEA, 0x71, 0x6C, 0x07, 0x56, 0xC5, 0x08, 0x0B, 0xE2, 0x39, 0x44, 0xAF, 0x8E, 
    0xCD, 0x20, 0xF3, 0x5A, 0x81, 0x9C, 0xD7, 0x46, 0x55, 0xB8, 0x5B, 0x52, 0x49, 0x74, 0x7F, 0x7E, 
    0x5D, 0xD0, 0x43, 0xCA, 0x91, 0xCC, 0xA7, 0x36, 0xE5, 0x68, 0xAB, 0xC2, 0x59, 0xA4, 0x4F, 0x6E, 
    0xED, 0x80, 0x93, 0x3A, 0xA1, 0xFC, 0x77, 0x26, 0x75, 0x18, 0xFB, 0x32, 0x69, 0xD4, 0x1F, 0x5E, 
    0x7D, 0x30, 0xE3, 0xAA, 0xB1, 0x2C, 0x47, 0x16, 0x05, 0xC8, 0x4B, 0xA2, 0x79, 0x04, 0xEF, 0x4E, 
    0x0D, 0xE0, 0x33, 0x1A, 0xC1, 0x5C, 0x17, 0x06, 0x95, 0x78, 0x9B, 0x12, 0x89, 0x34, 0xBF, 0x3E 
}; 
const unsigned char Key2[] = 
{ 
    0x62, 0x4F, 0xE8, 0x15, 0xDE, 0xEB, 0x04, 0x91, 0x1A, 0xC7, 0xE0, 0x4D, 0x16, 0xE3, 0x7C, 0x49, 
    0xD2, 0x3F, 0xD8, 0x85, 0x4E, 0xDB, 0xF4, 0x01, 0x8A, 0xB7, 0xD0, 0xBD, 0x86, 0xD3, 0x6C, 0xB9, 
    0x42, 0x2F, 0xC8, 0xF5, 0xBE, 0xCB, 0xE4, 0x71, 0xFA, 0xA7, 0xC0, 0x2D, 0xF6, 0xC3, 0x5C, 0x29, 
    0xB2, 0x1F, 0xB8, 0x65, 0x2E, 0xBB, 0xD4, 0xE1, 0x6A, 0x97, 0xB0, 0x9D, 0x66, 0xB3, 0x4C, 0x99, 
    0x22, 0x0F, 0xA8, 0xD5, 0x9E, 0xAB, 0xC4, 0x51, 0xDA, 0x87, 0xA0, 0x0D, 0xD6, 0xA3, 0x3C, 0x09, 
    0x92, 0xFF, 0x98, 0x45, 0x0E, 0x9B, 0xB4, 0xC1, 0x4A, 0x77, 0x90, 0x7D, 0x46, 0x93, 0x2C, 0x79, 
    0x02, 0xEF, 0x88, 0xB5, 0x7E, 0x8B, 0xA4, 0x31, 0xBA, 0x67, 0x80, 0xED, 0xB6, 0x83, 0x1C, 0xE9, 
    0x72, 0xDF, 0x78, 0x25, 0xEE, 0x7B, 0x94, 0xA1, 0x2A, 0x57, 0x70, 0x5D, 0x26, 0x73, 0x0C, 0x59, 
    0xE2, 0xCF, 0x68, 0x95, 0x5E, 0x6B, 0x84, 0x11, 0x9A, 0x47, 0x60, 0xCD, 0x96, 0x63, 0xFC, 0xC9, 
    0x52, 0xBF, 0x58, 0x05, 0xCE, 0x5B, 0x74, 0x81, 0x0A, 0x37, 0x50, 0x3D, 0x06, 0x53, 0xEC, 0x39, 
    0xC2, 0xAF, 0x48, 0x75, 0x3E, 0x4B, 0x64, 0xF1, 0x7A, 0x27, 0x40, 0xAD, 0x76, 0x43, 0xDC, 0xA9, 
    0x32, 0x9F, 0x38, 0xE5, 0xAE, 0x3B, 0x54, 0x61, 0xEA, 0x17, 0x30, 0x1D, 0xE6, 0x33, 0xCC, 0x19, 
    0xA2, 0x8F, 0x28, 0x55, 0x1E, 0x2B, 0x44, 0xD1, 0x5A, 0x07, 0x20, 0x8D, 0x56, 0x23, 0xBC, 0x89, 
    0x12, 0x7F, 0x18, 0xC5, 0x8E, 0x1B, 0x34, 0x41, 0xCA, 0xF7, 0x10, 0xFD, 0xC6, 0x13, 0xAC, 0xF9, 
    0x82, 0x6F, 0x08, 0x35, 0xFE, 0x0B, 0x24, 0xB1, 0x3A, 0xE7, 0x00, 0x6D, 0x36, 0x03, 0x9C, 0x69, 
    0xF2, 0x5F, 0xF8, 0xA5, 0x6E, 0xFB, 0x14, 0x21, 0xAA, 0xD7, 0xF0, 0xDD, 0xA6, 0xF3, 0x8C, 0xD9 
}; 

// Decrypt Function 
void CAuthCryptography::Decrypt(void* in, void* out, int Length) 
{ 
    unsigned char* pIn = (unsigned char*)in; 
    unsigned char* pOut = (unsigned char*)out; 
    for (int i = 0; i < Length; i++) 
    { 
     pOut[i] = (unsigned char)(pIn[i]^0xAB); 
     pOut[i] = (unsigned char)((pOut[i] << 4) | (pOut[i] >> 4)); 
     if (UsingAlternate) 
     { 
      pOut[i] = (unsigned char)(Key4[In.High]^pOut[i]); 
      pOut[i] = (unsigned char)(Key3[In.Low]^pOut[i]); 
     } 
     else 
     { 
      pOut[i] = (unsigned char)(Key2[In.High]^pOut[i]); 
      pOut[i] = (unsigned char)(Key1[In.Low]^pOut[i]); 
     } 
     In.Counter++; 
    } 
}

我得到了這段代碼，它的工作，但可以有人向我解釋它是如何工作的，因爲我不明白它？！或者如果有嘖嘖聲。我可以讀或什麼

來源

2011-01-21 Abanoub

嘗試使用Google搜索：反向工程網絡協議。 – ssmir 2011-01-21 07:10:16

我建議你使用像WireShark，tcpdump等東西來查看TCP流，只是爲了確保你沒有bodged你的tcp數據閱讀代碼。更一般地說，如果你正在獲取這樣的數據，那麼只有發送方會知道原因，並且你要麼詢問他們，要麼查看他們已經做出的其他接收程序如何處理這些數據（即調試另一個客戶端，找出它如何處理這個爛攤子）。

來源

2011-01-21 07:07:45

當它真的被加密時，您的機會很低。

但是很可能它只是UTF-7或UTF-8編碼，沒有加密。如果是非標準端口上的SSL，請使用oSpy。

來源

2011-01-21 07:14:01

C++從遊戲客戶端解密msg

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