這是MYSQL還是PHP錯誤？當mysql_fetch_array

我有這樣的錯誤：這是MYSQL還是PHP錯誤？當mysql_fetch_array

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\lab\try.php on line 40

查詢是：

$graphquery = mysql_query ("SELECT 
    $cluster, 
    SUM(IF(idx=3,1,0)) AS green, 
    SUM(IF(idx=2,1,0)) AS yellow, 
    SUM(IF(idx=1,1,0)) AS red 
FROM (SELECT 
     $cluster 
     $xcond 
     ,LEAST(999 $acond) idx 
     FROM table 
     WHERE date >= '". $startDate ."' 
      AND date <= '". $endDate ."' 
      AND $regional = '$gregcond' 
      AND $latitude IS NOT NULL 
     GROUP BY $cluster, $lac, $mainid 
     HAVING $cluster IS NOT NULL 
$paraxcond 
    ) A 
GROUP BY $cluster");

如果我回應查詢時，它會像這樣（沒有錯誤，完美的結果也BTW）：

SELECT 
    cluster, 
    SUM(IF(idx=3,1,0)) AS green, 
    SUM(IF(idx=2,1,0)) AS yellow, 
    SUM(IF(idx=1,1,0)) AS red 
FROM (SELECT 
     cluster, 
     ROUND(AVG(some_value_Index)) some_value_Index, 
     LEAST(999, AVG(some_value_Index)) idx 
     FROM TABLE 
     WHERE tanggal >= '2012-07-10' 
      AND tanggal <= '2012-08-02' 
      AND Regional = 'Regional_Example' 
      AND Latitude IS NOT NULL 
     GROUP BY cluster, Lac, ID 
     HAVING cluster IS NOT NULL 
      AND some_value_Index IN(3,2,1)) A 
GROUP BY cluster

當我對腳本添加mysql_error，這聽起來像這樣：

Incorrect parameter count in the call to native function 'LEAST'

這裏是如何我願意用MySQL查詢：

$row = mysql_fetch_array ($graphquery)

當我回聲查詢並嘗試在SQLyog的或PHPMYADMIN有沒有包含錯誤，那麼誰能告訴我哪裏是請錯誤？

來源

2012-08-02 Anggie Aziz

最新的$內容acond？ – Hawili 2012-08-02 04:17:47

你不會告訴我們什麼是'$ graphquery'，而你使用'mysql_'，這更糟糕。開始使用'PDO'或'MySQLi'。 – alfasin 2012-08-02 04:23:49

$ acond和$ xcond只是一個條件bro，我認爲沒有什麼會影響腳本的。查詢太複雜，我想，所以我不能解釋更多的細節。但我會等待你的答案或另一個問題來清除它:)謝謝btw – 2012-08-02 04:23:58

您錯過了LEAST（）函數中的逗號。至少需要2個或更多參數。所以查詢將會是。

mysql_query ("SELECT 
    $cluster, 
    SUM(IF(idx=3,1,0)) AS green, 
    SUM(IF(idx=2,1,0)) AS yellow, 
    SUM(IF(idx=1,1,0)) AS red 
FROM (SELECT 
     $cluster 
     $xcond 
     ,LEAST(999, $acond) idx 
     FROM table 
     WHERE date >= '". $startDate ."' 
      AND date <= '". $endDate ."' 
      AND $regional = '$gregcond' 
      AND $latitude IS NOT NULL 
     GROUP BY $cluster, $lac, $mainid 
     HAVING $cluster IS NOT NULL 
$paraxcond 
    ) A 
GROUP BY $cluster");

我改變LEAST(999 $acond)到LEAST(999, $acond)

來源

2012-08-02 04:25:31

感謝隊友，但再次檢查問題，它可能會更清楚地理解：D – 2012-08-02 04:30:34

這是MYSQL還是PHP錯誤？當mysql_fetch_array

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