Java程序在直角三角形中顯示名稱？

Question

嗨，我想做出一個直角三角形的形式顯示名稱的程序，但我這個節目的另一側輸出是

import java.util.Scanner; 
public class NameGame2 { 
    public static void main(String[]args) 
    { 
     Scanner x = new Scanner(System.in); 
     String name, name2 = ""; 
     System.out.print("What is your name : "); 
     name = x.nextLine(); 
     System.out.println(); 
     for(int i=0; i<name.length(); i++) { 
      name2 = name2 + name.charAt(i); 
      System.out.println(name2); 
     } System.out.print("\n"); 
    } 
} 

---

I want the output to be like this  outputof my code is 
     R         A 
     ER         AS 
    HER         ASH 
    SHER         ASHE 
    ASHER         ASHER 

Answer 1

試試這個，你需要一個循環的空間，字符應該從去年index.Full代碼開始

Scanner x = new Scanner(System. in); 
System.out.print("What is your name : "); 
String name = x.nextLine(); 
System.out.println(); 
for (int i = name.length() - 1; i >= 0; i--) { 

    for (int k = 0; k <= i; k++) 
    System.out.print(" "); 

    for (int j = i; j <= name.length() - 1; j++) { 
     System.out.print(name.charAt(j)); 
    } 
    System.out.println(); 
} 

輸出

 R 
    ER 
    HER 
    SHER 
ASHER 

DEMO

Answer 2

Java的解決方案8：

import java.util.Scanner; 
import java.util.stream.IntStream; 

public class NameGame2 { 
    public static void main(String[] args) { 
     System.out.print("What is your name : "); 
     String name = new Scanner(System.in).nextLine(); 
     IntStream.rangeClosed(1, name.length()) 
      .mapToObj(pos -> String.format("%" + name.length() + "s", 
          name.substring(name.length() - pos))) 
      .forEach(System.out::println); 
    } 
}