此問題是對以前的問題的修改,我覺得我以不清楚的方式提出了問題。我正在檢查列V1和V2是否按行排列公共代碼。代碼以正斜槓「/」分隔。下面的函數應該從V1中獲取一個單元格,並從同一行的V2中獲取一個單元格,並將其轉換爲向量。矢量的每個元素都是一個代碼。然後函數應該檢查所獲得的兩個向量是否有共同的元素。這些元素最初是4位數字代碼。如果有兩個向量匹配的4位代碼,函數應該返回4.如果沒有共同的元素,函數應該減少每個代碼的位數,然後再次檢查。每次函數減少數字位數時,它也會降低最後返回的分數。我希望函數返回的值寫在我選擇的列中。如何將與data.frame單元格一起使用的函數應用於data.frame列
這是我的出發條件
structure(list(ID = c(2630611040, 2696102020, 2696526020), V1 = c("7371/3728",
"2834/2833/2836/5122/8731", "3533/3541/3545/5084"), V2 = c("7379",
"3841", "3533/3532/3531/1389/8711")), .Names = c("ID", "V1",
"V2"), class = "data.frame", row.names = c(NA, 3L))
ID V1 V2
1 2630611040 7371/3728 7379
2 2696102020 2834/2833/2836/5122/8731 3841
3 2696526020 3533/3541/3545/5084 3533/3532/3531/1389/8711
而且我想獲得這個
ID V1 V2 V3
1 2630611040 7371/3728 7379 3
2 2696102020 2834/2833/2836/5122/8731 3841 0
3 2696526020 3533/3541/3545/5084 3533/3532/3531/1389/8711 4
我的功能是本
coderelat<-function(a, b){
a<-unique(as.integer(unlist(str_split(a, "/")))) #Transforming cells into vectors of codes
b<-unique(as.integer(unlist(str_split(b, "/"))))
a<-a[!is.na(a)]
b<-b[!is.na(b)]
if (length(a)==0 | length(b)==0) { # Check that both cells are not empty
ir=NA
return(ir)
} else {
for (i in 3:1){
diff<-intersect(a, b) # See how many products the shops have in common
if (length(diff)!=0) { #As you find a commonality, give ir the corresponding scoring
ir=i+1
break
} else if (i==1 & length(diff)==0) { #If in the last cycle, there is still no commonality put ir=0
ir=0
break
} else { # If there is no commonality and you are not in the last cycle, reduce the nr. of digits and re-check commonality again
a<- unique(as.integer(substr(as.character(a), 1, i)))
b<- unique(as.integer(substr(as.character(b), 1, i)))
}
}
}
return(ir)
}
起步控制功能時,我手動提供單個細胞。
df$V4<-coderelat(df$V1, df$V2)
我真的很感激任何幫助,因爲我不知道怎麼了,以使這項工作:但是,當我寫soemthing這樣是行不通的。
非常感謝提前。 Riccardo
使用'dput(...)'提供您的數據非常有用(+1)。 – jlhoward 2014-11-20 21:40:21