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我正在使用jQuery表單插件http://jquery.malsup.com/form/#getting-started通過ajax上傳圖像。當我試圖把它上傳顯示該模型沒有_committed 這裏的屬性是我的HTML:模型沒有屬性_committed
<form id="uploadform" method="post" enctype="multipart/form-data" action="/cover/">{% csrf_token %}
{{ form.background }}
</form>
的Javascript:
https://gist.github.com/2381406
Models.py:
class BackgroundModel(models.Model):
user = models.OneToOneField(User)
background = models.ImageField(upload_to='backgrounds')
class BackgroundModelForm(ModelForm):
class Meta:
model = BackgroundModel
exclude = ('user',)
意見。 py:
@login_required
def backgroundview(request):
if request.is_ajax():
form = BackgroundModelForm(request.POST, request.FILES)
if form.is_valid():
try:
g = BackgroundModel.objects.get(user=request.user)
except BackgroundModel.DoesNotExist:
data = form.save(commit=False)
data.user = request.user
data.save()
else:
g.background = form
g.save()
HttpResponse(" ")
else:
form = BackgroundModelForm()
return render_to_response("cover.html", {'form': form}, context_instance=RequestContext(request))
Urls.py:
url(r'^cover/$', 'cover.views.backgroundview'),
能否使用此代碼爲ModelForm? – rnk 2012-04-14 05:05:05
@mk是的,或者你可以在else分支中執行'BackgroundModelForm(request.POST,request.FILES,instance = g).save()'。 – okm 2012-04-14 05:18:18