2012-04-14 82 views
2

我正在使用jQuery表單插件http://jquery.malsup.com/form/#getting-started通過ajax上傳圖像。當我試圖把它上傳顯示該模型沒有_committed 這裏的屬性是我的HTML:模型沒有屬性_committed

<form id="uploadform" method="post" enctype="multipart/form-data" action="/cover/">{% csrf_token %} 
     {{ form.background }} 
</form> 

的Javascript:

https://gist.github.com/2381406

Models.py:

class BackgroundModel(models.Model): 
    user = models.OneToOneField(User) 
    background = models.ImageField(upload_to='backgrounds') 

class BackgroundModelForm(ModelForm): 
    class Meta: 
     model = BackgroundModel 
     exclude = ('user',) 

意見。 py:

@login_required 
def backgroundview(request): 
    if request.is_ajax(): 
     form = BackgroundModelForm(request.POST, request.FILES) 
     if form.is_valid(): 
      try: 
       g = BackgroundModel.objects.get(user=request.user) 
      except BackgroundModel.DoesNotExist: 
       data = form.save(commit=False) 
       data.user = request.user 
       data.save() 
      else: 
       g.background = form 
       g.save() 
      HttpResponse(" ") 
    else: 
     form = BackgroundModelForm() 
    return render_to_response("cover.html", {'form': form}, context_instance=RequestContext(request)) 

Urls.py:

url(r'^cover/$', 'cover.views.backgroundview'), 

回答

2

代替g.background = form在else分支,嘗試

try: 
    g = BackgroundModel.objects.get(user=request.user) 
except BackgroundModel.DoesNotExist: 
    data = form.save(commit=False) 
    data.user = request.user 
    data.save() 
else: 
    g.background = form.save(commit=False).background 
    g.save() 
    # or 
    BackgroundModelForm(request.POST, request.FILES, instance=g).save() 

只有接受的類型的值可以被分配到一個模型實例的相應字段。這裏
models.ImageField接受

  • 文件路徑字符串
  • django.db.models.fields.files.ImageFieldFile
  • django.core.files.images.ImageFile
+0

能否使用此代碼爲ModelForm? – rnk 2012-04-14 05:05:05

+0

@mk是的,或者你可以在else分支中執行'BackgroundModelForm(request.POST,request.FILES,instance = g).save()'。 – okm 2012-04-14 05:18:18

相關問題