是否有可能以及如何使用其四角扭曲爲非矩形的圖像進行繪製。例如,如果您想繪製圖像,就好像它已經在三維空間中旋轉一樣。在html5的畫布上繪製扭曲的圖像
2
A
回答
1
最簡單的方法是在繪製圖像之前將轉換應用於畫布。
http://www.whatwg.org/specs/web-apps/current-work/multipage/the-canvas-element.html#transformations
隨着傾斜的轉換,你可以使它看起來就像是在透視畫
這裏是一個非常簡單的例子:
ctx.setTransform (1, -0.2, 0, 1, 0, 0);
ctx.drawImage(blah);
1
看看這個教程,它採用光學幻覺模擬透視。 http://www.subshell.com/en/subshell/blog/image-manipulation-html5-canvas102.html
0
你可以試試function transferPoint (xI, yI, source, destination)
說明here。
源和目標是源矩形和目標矩形的四個點。該代碼適用於(SVG)路徑座標(曲線和線),但經過一些修改後也可以使用像素。
4
我創建了一個基於Thatcher Ulrich的代碼(http://tulrich.com/geekstuff/canvas/perspective.html)的簡單4點變換。該版本僅提取一小部分三角形代碼並處理幾何細分以進行適當的轉換。請享用!
http://jsfiddle.net/mrbendel/6rbtde5t/1/
var controls = [];
var canvas;
var context;
var image;
var triangles = [];
var dirtyTriangles = true;
var rand = function(s,e) {
return Math.random() * (e-s) + s;
}
// dom ready
$(document).ready(function() {
image = new Image();
$(image).load(function() {
setInterval(draw, 1000/60);
});
$(image).attr('src', 'http://media.giphy.com/media/NWb6sWXQQTqwg/giphy.gif');
canvas = document.createElement('canvas');
$(canvas).attr('width', 500);
$(canvas).attr('height', 500);
$('body').append(canvas);
context = canvas.getContext('2d');
//
for (var i = 0; i < 4; ++i) {
var control = document.createElement('div');
$(control).addClass('node');
$('body').append(control);
controls.push(control);
}
$(controls[0]).css('left', rand(25, 225));
$(controls[0]).css('top', rand(25, 225));
$(controls[1]).css('left', rand(250, 475));
$(controls[1]).css('top', rand(25, 225));
$(controls[2]).css('left', rand(250, 475));
$(controls[2]).css('top', rand(250, 475));
$(controls[3]).css('left', rand(25, 225));
$(controls[3]).css('top', rand(250, 475));
$('body').mousedown(function(e) {
if ($(e.target).hasClass('node')) {
var node = e.target;
$('body').mousemove(function(e) {
var x = e.pageX;
var y = e.pageY;
$(node).css('left', x);
$(node).css('top', y);
dirtyTriangles = true;
});
$('body').mouseup(function(e) {
$('body').off("mousemove");
$('body').off("mouseup");
});
}
});
});
var draw = function() {
context.clearRect(0,0,500,500);
var render = function(wireframe, image, tri) {
if (wireframe) {
context.strokeStyle = "black";
context.beginPath();
context.moveTo(tri.p0.x, tri.p0.y);
context.lineTo(tri.p1.x, tri.p1.y);
context.lineTo(tri.p2.x, tri.p2.y);
context.lineTo(tri.p0.x, tri.p0.y);
context.stroke();
context.closePath();
}
if (image) {
drawTriangle(context, image,
tri.p0.x, tri.p0.y,
tri.p1.x, tri.p1.y,
tri.p2.x, tri.p2.y,
tri.t0.u, tri.t0.v,
tri.t1.u, tri.t1.v,
tri.t2.u, tri.t2.v);
}
}
if (dirtyTriangles) {
dirtyTriangles = false;
calculateGeometry();
}
for (triangle of triangles) {
render(true, image, triangle);
}
}
var calculateGeometry = function() {
// clear triangles out
triangles = [];
// generate subdivision
var subs = 7; // vertical subdivisions
var divs = 7; // horizontal subdivisions
var p1 = new Point(parseInt($(controls[0]).css('left')) + 6, parseInt($(controls[0]).css('top')) + 6);
var p2 = new Point(parseInt($(controls[1]).css('left')) + 6, parseInt($(controls[1]).css('top')) + 6);
var p3 = new Point(parseInt($(controls[2]).css('left')) + 6, parseInt($(controls[2]).css('top')) + 6);
var p4 = new Point(parseInt($(controls[3]).css('left')) + 6, parseInt($(controls[3]).css('top')) + 6);
var dx1 = p4.x - p1.x;
var dy1 = p4.y - p1.y;
var dx2 = p3.x - p2.x;
var dy2 = p3.y - p2.y;
var imgW = image.naturalWidth;
var imgH = image.naturalHeight;
for (var sub = 0; sub < subs; ++sub) {
var curRow = sub/subs;
var nextRow = (sub + 1)/subs;
var curRowX1 = p1.x + dx1 * curRow;
var curRowY1 = p1.y + dy1 * curRow;
var curRowX2 = p2.x + dx2 * curRow;
var curRowY2 = p2.y + dy2 * curRow;
var nextRowX1 = p1.x + dx1 * nextRow;
var nextRowY1 = p1.y + dy1 * nextRow;
var nextRowX2 = p2.x + dx2 * nextRow;
var nextRowY2 = p2.y + dy2 * nextRow;
for (var div = 0; div < divs; ++div) {
var curCol = div/divs;
var nextCol = (div + 1)/divs;
var dCurX = curRowX2 - curRowX1;
var dCurY = curRowY2 - curRowY1;
var dNextX = nextRowX2 - nextRowX1;
var dNextY = nextRowY2 - nextRowY1;
var p1x = curRowX1 + dCurX * curCol;
var p1y = curRowY1 + dCurY * curCol;
var p2x = curRowX1 + (curRowX2 - curRowX1) * nextCol;
var p2y = curRowY1 + (curRowY2 - curRowY1) * nextCol;
var p3x = nextRowX1 + dNextX * nextCol;
var p3y = nextRowY1 + dNextY * nextCol;
var p4x = nextRowX1 + dNextX * curCol;
var p4y = nextRowY1 + dNextY * curCol;
var u1 = curCol * imgW;
var u2 = nextCol * imgW;
var v1 = curRow * imgH;
var v2 = nextRow * imgH;
var triangle1 = new Triangle(
new Point(p1x, p1y),
new Point(p3x, p3y),
new Point(p4x, p4y),
new TextCoord(u1, v1),
new TextCoord(u2, v2),
new TextCoord(u1, v2)
);
var triangle2 = new Triangle(
new Point(p1x, p1y),
new Point(p2x, p2y),
new Point(p3x, p3y),
new TextCoord(u1, v1),
new TextCoord(u2, v1),
new TextCoord(u2, v2)
);
triangles.push(triangle1);
triangles.push(triangle2);
}
}
}
// from http://tulrich.com/geekstuff/canvas/jsgl.js
var drawTriangle = function(ctx, im, x0, y0, x1, y1, x2, y2,
sx0, sy0, sx1, sy1, sx2, sy2) {
ctx.save();
// Clip the output to the on-screen triangle boundaries.
ctx.beginPath();
ctx.moveTo(x0, y0);
ctx.lineTo(x1, y1);
ctx.lineTo(x2, y2);
ctx.closePath();
//ctx.stroke();//xxxxxxx for wireframe
ctx.clip();
/*
ctx.transform(m11, m12, m21, m22, dx, dy) sets the context transform matrix.
The context matrix is:
[ m11 m21 dx ]
[ m12 m22 dy ]
[ 0 0 1 ]
Coords are column vectors with a 1 in the z coord, so the transform is:
x_out = m11 * x + m21 * y + dx;
y_out = m12 * x + m22 * y + dy;
From Maxima, these are the transform values that map the source
coords to the dest coords:
sy0 (x2 - x1) - sy1 x2 + sy2 x1 + (sy1 - sy2) x0
[m11 = - -----------------------------------------------------,
sx0 (sy2 - sy1) - sx1 sy2 + sx2 sy1 + (sx1 - sx2) sy0
sy1 y2 + sy0 (y1 - y2) - sy2 y1 + (sy2 - sy1) y0
m12 = -----------------------------------------------------,
sx0 (sy2 - sy1) - sx1 sy2 + sx2 sy1 + (sx1 - sx2) sy0
sx0 (x2 - x1) - sx1 x2 + sx2 x1 + (sx1 - sx2) x0
m21 = -----------------------------------------------------,
sx0 (sy2 - sy1) - sx1 sy2 + sx2 sy1 + (sx1 - sx2) sy0
sx1 y2 + sx0 (y1 - y2) - sx2 y1 + (sx2 - sx1) y0
m22 = - -----------------------------------------------------,
sx0 (sy2 - sy1) - sx1 sy2 + sx2 sy1 + (sx1 - sx2) sy0
sx0 (sy2 x1 - sy1 x2) + sy0 (sx1 x2 - sx2 x1) + (sx2 sy1 - sx1 sy2) x0
dx = ----------------------------------------------------------------------,
sx0 (sy2 - sy1) - sx1 sy2 + sx2 sy1 + (sx1 - sx2) sy0
sx0 (sy2 y1 - sy1 y2) + sy0 (sx1 y2 - sx2 y1) + (sx2 sy1 - sx1 sy2) y0
dy = ----------------------------------------------------------------------]
sx0 (sy2 - sy1) - sx1 sy2 + sx2 sy1 + (sx1 - sx2) sy0
*/
// TODO: eliminate common subexpressions.
var denom = sx0 * (sy2 - sy1) - sx1 * sy2 + sx2 * sy1 + (sx1 - sx2) * sy0;
if (denom == 0) {
return;
}
var m11 = -(sy0 * (x2 - x1) - sy1 * x2 + sy2 * x1 + (sy1 - sy2) * x0)/denom;
var m12 = (sy1 * y2 + sy0 * (y1 - y2) - sy2 * y1 + (sy2 - sy1) * y0)/denom;
var m21 = (sx0 * (x2 - x1) - sx1 * x2 + sx2 * x1 + (sx1 - sx2) * x0)/denom;
var m22 = -(sx1 * y2 + sx0 * (y1 - y2) - sx2 * y1 + (sx2 - sx1) * y0)/denom;
var dx = (sx0 * (sy2 * x1 - sy1 * x2) + sy0 * (sx1 * x2 - sx2 * x1) + (sx2 * sy1 - sx1 * sy2) * x0)/denom;
var dy = (sx0 * (sy2 * y1 - sy1 * y2) + sy0 * (sx1 * y2 - sx2 * y1) + (sx2 * sy1 - sx1 * sy2) * y0)/denom;
ctx.transform(m11, m12, m21, m22, dx, dy);
// Draw the whole image. Transform and clip will map it onto the
// correct output triangle.
//
// TODO: figure out if drawImage goes faster if we specify the rectangle that
// bounds the source coords.
ctx.drawImage(im, 0, 0);
ctx.restore();
};
// point class
var Point = function(x,y) {
this.x = x?x:0;
this.y = y?y:0;
}
var p = Point.prototype;
p.length = function(point) {
point = point?point:new Point();
var xs =0, ys =0;
xs = point.x - this.x;
xs = xs * xs;
ys = point.y - this.y;
ys = ys * ys;
return Math.sqrt(xs + ys);
}
var TextCoord = function(u,v) {
this.u = u?u:0;
this.v = v?v:0;
}
var Triangle = function(p0, p1, p2, t0, t1, t2) {
this.p0 = p0;
this.p1 = p1;
this.p2 = p2;
this.t0 = t0;
this.t1 = t1;
this.t2 = t2;
}
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的setTransform讓你指定一個2×3矩陣。要做一個適當的角度(不是等角或正交),你需要一個4×4不是嗎? – 2010-11-04 15:44:54
哦,你是對的。抱歉。儘管如此,還是有一些駭人的嘗試。看到這裏:http://tulrich.com/geekstuff/canvas/perspective.html – 2010-11-04 16:30:04