compare int with char

Question

這是我的program的代碼片段，其中當輸入要求的值時，增加該變量的值，並在按下鍵q後退出循環來打印結果。請注意，我的代碼通過從用戶sys導入argv的參數（這就是爲什麼我的名字在命令行中）。

prompt = "# " 
come_out = True 
one = 0 
two = 0 
three = 0 
four = 0 
answer = 0 

while (come_out == True): 
    print """ 
    Enter q to exit() 
    > Do you like Got? 
    > What about LoTR? 
    > Okay, Fargo? 
    > Alright, last choice: American Gods? 
    """ 
answer = raw_input(prompt) 
if answer == 1: 
    one = one + 1 
elif answer == 2: 
    two = two + 1 
elif answer == 3: 
    three = three + 1 
elif answer == 4: 
    four = four + 1 
elif answer == ord('q'): 
    come_out = False  
else: 
    print "Not applicable ~~~ exiting" 
    come_out = False 

當我被命令執行腳本：

$ python ex14.py Sambhav-Jain

它不給任何錯誤，但作爲假設不工作，因爲它必須通過的循環，直至跑一路用戶明確按下鍵q退出，但：

Hi, Sambhav-Jain. Welcome to your ex14.py script. 

Enter q to exit() 
> Do you like Got? 
> What about LoTR? 
> Okay, Fargo? 
> Alright, last choice: American Gods? 

# 1 
Not applicable ~~~ exiting 

GoT Lovers: 0 
LoTR Lovers: 0 
Fargo Lovers: 0 
American God Lovers: 0 

然後我在網上搜索，發現了一種顯式轉換answer變量int即：

answer = int(raw_input(prompt)) 

通過這樣做，並執行我用以前的版本相同的命令，它會產生一個錯誤：

Hi, Sambhav-Jain. Welcome to your ex14.py script. 

Enter q to exit() 
> Do you like Got? 
> What about LoTR? 
> Okay, Fargo? 
> Alright, last choice: American Gods? 

# 1 

Enter q to exit() 
> Do you like Got? 
> What about LoTR? 
> Okay, Fargo? 
> Alright, last choice: American Gods? 

# q 
Traceback (most recent call last): 
File "ex14.py", line 26, in <module> 
    answer = int(raw_input(prompt)) 
ValueError: invalid literal for int() with base 10: 'q' 

PS：請不要將此標記爲重複。

Answer 1

raw_input()返回一個字符串。

因此，您需要將其轉換或僅與字符串進行比較。

如果你改變你的攀比：

if answer == '1': 
    one = one + 1 
elif answer == '2': 
    two = two + 1 
elif answer == '3': 
    three = three + 1 
elif answer == '4': 
    four = four + 1 
elif answer == 'q': 
    come_out = False  

，你希望它會工作。