我可以將兩個選擇元素中的值分配給一個變量嗎？

我是相當新的PHP和我有這種代碼的各種問題基本上我想添加2個選擇選項的時間值到一個變量，然後將該變量存儲爲我的數據庫中的時間。我不清楚如何發佈一個包含兩個值的變量，它可能通過數組實現，但我已經嘗試過，並且只是說它沒有結果，請參閱下面的代碼。我可以將兩個選擇元素中的值分配給一個變量嗎？

此外，如果它通過PHP，建議將更有用，請參閱圖像的形式。

<?php 


//connect to db 
include 'connect.php'; 

//This is the directory where images will be saved 
$event_type = $_POST['event_type']; 
$title = strip_tags($_POST['title']); 
$description = strip_tags($_POST['description']); 
$date = strip_tags ($_POST['date']); 
$stime = $_POST['stime']); 
$etime = $_POST['etime']) 
$add1 = strip_tags($_POST['address1']); 
$add2 = strip_tags($_POST['address2']); 
$city = strip_tags($_POST['city']); 
$postcode = strip_tags($_POST['postcode']); 
$country = strip_tags($_POST['country']); 
$tick = strip_tags($_POST['tkqty']); 
$price = strip_tags($_POST['price']); 
$now = time(); 

$image_name = addslashes($_FILES['image']['name']); 
$image_tmpname = addslashes($_FILES['image']['tmp_name']); 
$image_size = getimagesize($_FILES['image']['tmp_name']); 



if (strtotime($date) < $now) { 
echo $errormsg = "that date is not valid";} 



if ($image_size==FALSE) 
echo "That is not an image"; 
else 
{ 
if ($image_name) 


$target = "uploaded/$image_name"; 
move_uploaded_file($_FILES['image']['tmp_name'],$target); 
$user = $_SESSION['user_id']; 

mysql_query ("INSERT into events VALUES('','$event_type','$title','$description','$date','$stime','$etime','$target','$add1','$add2','$city','$postcode','$country','$tick','$price','$user')"); 

    //Tells you if its all ok 
    echo "<h2> Event Add Successful</h2>"; 
    echo "Your event : ".$title." is now live, please return to <a href='manage_event.php'>manage   event</a> area. "; 
    } 


?>

enter image description here