我有以下型號Ruby on Rails的/ SQL查詢與
class Company < ActiveRecord::Base
attr_accessible :name, address, ........
has_many :employees
end
class Employee < ActiveRecord::Base
attr_accessible :firstname, :lastname, :company_id, .............
belongs_to :company
end
我有一個字符串q和想選擇所有員工衛生組織名姓或company.name像Q,沿着線的東西此查詢非工作查詢
Employee.where("firstname like ? or lastname like ? or company.name like ?", q,q,q)
什麼是最好的方式來實現這與軌?