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我當前使用SELECT PDO,但我有此錯誤消息SQLSTATE [23000]:完整性約束違規:1062重複項 'XXXX' 關鍵 'group_key'
SELECT a.*, UNIX_TIMESTAMP(a.createdon) AS timestamp, ct.cityname, ct.SeoCityName, scat.subcatname, scat.SeoSubcatName, COUNT(*) AS piccount, p.picfile, UNIX_TIMESTAMP(feat.featuredtill) AS featuredtill FROM prefix_ads a INNER JOIN prefix_cities ct ON a.cityid = ct.cityid INNER JOIN prefix_subcats scat ON a.subcatid = scat.subcatid LEFT OUTER JOIN prefix_adxfields axf ON a.adid = axf.adid LEFT OUTER JOIN prefix_adpics p ON a.adid = p.adid AND p.isevent = '0' LEFT OUTER JOIN prefix_featured feat ON a.adid = feat.adid AND feat.adtype = 'A' WHERE a.catid = '10' AND a.enabled = '1' AND a.verified = '1' AND a.expireson >= NOW() GROUP BY a.adid ORDER BY a.createdon DESC LIMIT 0, 18
SQLSTATE [23000]:誠信約束衝突:1062重複項「XXXX」關鍵「group_key」
XXXX =曾經是,如果上市
可以有人請幫助?
EXPLAIN
Array ( [id] => 1 [0] => 1 [select_type] => SIMPLE [1] => SIMPLE [table] => scat [2] => scat [type] => ALL [3] => ALL [possible_keys] => PRIMARY [4] => PRIMARY [key] => [5] => [key_len] => [6] => [ref] => [7] => [rows] => 152 [8] => 152 [filtered] => 100.00 [9] => 100.00 [Extra] => Using temporary; Using filesort [10] => Using temporary; Using filesort ) Array ( [id] => 1 [0] => 1 [select_type] => SIMPLE [1] => SIMPLE [table] => a [2] => a [type] => ref [3] => ref [possible_keys] => subcatid,cityid,verified,enabled,expireson,catid,ct_ads [4] => subcatid,cityid,verified,enabled,expireson,catid,ct_ads [key] => subcatid [5] => subcatid [key_len] => 2 [6] => 2 [ref] => DB.scat.subcatid [7] => DB.scat.subcatid [rows] => 150 [8] => 150 [filtered] => 100.00 [9] => 100.00 [Extra] => Using where [10] => Using where ) Array ( [id] => 1 [0] => 1 [select_type] => SIMPLE [1] => SIMPLE [table] => ct [2] => ct [type] => eq_ref [3] => eq_ref [possible_keys] => PRIMARY [4] => PRIMARY [key] => PRIMARY [5] => PRIMARY [key_len] => 2 [6] => 2 [ref] => DB.a.cityid [7] => DB.a.cityid [rows] => 1 [8] => 1 [filtered] => 100.00 [9] => 100.00 [Extra] => [10] => ) Array ( [id] => 1 [0] => 1 [select_type] => SIMPLE [1] => SIMPLE [table] => axf [2] => axf [type] => ref [3] => ref [possible_keys] => adid [4] => adid [key] => adid [5] => adid [key_len] => 4 [6] => 4 [ref] => DB.a.adid [7] => DB.a.adid [rows] => 1 [8] => 1 [filtered] => 100.00 [9] => 100.00 [Extra] => Using index [10] => Using index ) Array ( [id] => 1 [0] => 1 [select_type] => SIMPLE [1] => SIMPLE [table] => p [2] => p [type] => ref [3] => ref [possible_keys] => adid [4] => adid [key] => adid [5] => adid [key_len] => 5 [6] => 5 [ref] => DB.a.adid,const [7] => DB.a.adid,const [rows] => 1 [8] => 1 [filtered] => 100.00 [9] => 100.00 [Extra] => [10] => ) Array ( [id] => 1 [0] => 1 [select_type] => SIMPLE [1] => SIMPLE [table] => feat [2] => feat [type] => eq_ref [3] => eq_ref [possible_keys] => adid [4] => adid [key] => adid [5] => adid [key_len] => 7 [6] => 7 [ref] => DB.a.adid,const [7] => DB.a.adid,const [rows] => 1 [8] => 1 [filtered] => 100.00 [9] => 100.00 [Extra] => [10] => )
id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE scat ALL PRIMARY NULL NULL NULL 152 Using temporary; Using filesort 1 SIMPLE a ref subcatid,cityid,verified,enabled,expireson,catid,c... subcatid 2 DB.scat.subcatid 150 Using where 1 SIMPLE ct eq_ref PRIMARY PRIMARY 2 DB.a.cityid 1 1 SIMPLE axf ref adid adid 4 DB.a.adid 1 Using index 1 SIMPLE p ref adid adid 5 DB.a.adid,const 1 1 SIMPLE feat eq_ref adid adid 7 DB.a.adid,const 1
問候 摹
我沒有看到任何插入或更新 – 2013-04-28 23:54:01
是的,有沒有插入或更新,但我在我的網站有這個問題。這就是我要求你的專家幫忙的原因。 – 2013-04-29 07:37:08