如何處理SQLSTATE [23000]：完整性約束違規：1062

Question

一切工作在我的代碼但是如果你要創建一個用戶它將接受，即使你使用相同的電子郵件創建一個多用戶我已經嘗試搜索一些解決方案並把它放在我的代碼中，但我仍然無法使它工作，我怎樣才能使SQLSTATE [23000]：完整性約束違規：1062變成「錯誤電子郵件已存在」？可能嗎？

addform.php

，我也想，如果有重複的

<style type="text/css"> 
#dis{ 
display:none; 
} 
</style> 




<div id="dis"> 
<!-- here message will be displayed --> 
</div> 


<form method='post' id='emp-SaveForm' action="#"> 

<table class='table table-bordered'> 

    <tr> 
     <td>First Name</td> 
     <td><input type='text' name='fname' class='form-control' required /></td> 
    </tr> 

    <tr> 
     <td>Last Name</td> 
     <td><input type='text' name='lname' class='form-control' required></td> 
    </tr> 

    <tr> 
     <td>Contact Number</td> 
     <td><input type='number' name='contactnum' class='form-control' required></td> 
    </tr> 

    <tr> 
     <td>Email</td> 
     <td><input type='email' name='email' class='form-control' required /></td> 
    </tr> 

    <tr> 
     <td>Password</td> 
     <td><input type="password" name='pass' class='form-control' required /></td> 
    </tr> 

    <tr> 
     <td>Language</td> 
     <td><input type='text' name='lang' class='form-control' required /></td> 
    </tr> 
    <tr> 
     <td colspan="2"> 
     <button type="submit" class="btn btn-primary" name="btn-save" id="btn-save"> 
     <span class="glyphicon glyphicon-plus"></span> Save this User 
     </button> 
     </td> 
    </tr> 

</table> 

create.php

<?php 
require_once 'dbconfig.php'; 


if($_POST) 
{ 
    $fname = $_POST['fname']; 
    $lname = $_POST['lname']; 
    $contactnum = $_POST['contactnum']; 
    $email = $_POST['email']; 
    $pass = $_POST['pass']; 
    $lang = $_POST['lang']; 
    try{ 

     $stmt = $db_con->prepare("INSERT INTO tbluser(fname,lname,contactnum,email,pass,lang) VALUES(:ufname,:ulname,:ucontact,:uemail,:upass,:ulang)"); 
     $stmt->bindParam(":ufname", $fname); 
     $stmt->bindParam(":ulname", $lname); 
     $stmt->bindParam(":ucontact", $contactnum); 
     $stmt->bindParam(":uemail", $email); 
     $stmt->bindParam(":upass", $pass); 
     $stmt->bindParam(":ulang", $lang); 
     if($stmt->execute()) 
     { 
      echo "Successfully Added"; 
     } 
     else{ 
      echo "Query Problem"; 
     } 
    } 
    catch(PDOException $e){ 
     echo $e->getMessage(); 
    } 
} 

?> 

我只是顯示一個錯誤信息新的PHP我在數據庫中使用PDO不知道它是否是一件好事，無論如何感謝幫助和幫助ase讓我知道，如果我可以使用或只是複製粘貼你的代碼或不:)

Answer 1

你應該編輯你的create.php並添加電子郵件檢查代碼數據庫，請檢查以下代碼，以獲得更多的想法。

<?php 
require_once 'dbconfig.php'; 


if ($_POST) { 

    $fname = $_POST['fname']; 
    $lname = $_POST['lname']; 
    $contactnum = $_POST['contactnum']; 
    $email = $_POST['email']; 
    $pass = $_POST['pass']; 
    $lang = $_POST['lang']; 

    // it's good habit to validate email address always 
    // i checked here it should not be blank 
    if ($email != '') { 

     // check in database email address is already taken 
     $sel = $db_con->prepare("select email from tbluser where email = :email"); 
     $sel->execute(array(':email' => $email)); 
     $row = $sel->fetch(); 

     // if you found any row with current entered email then send it to else 
     if ($sel->fetchColumn() == 0) { 
      try{ 
       $stmt = $db_con->prepare("INSERT INTO tbluser(fname,lname,contactnum,email,pass,lang) VALUES(:ufname,:ulname,:ucontact,:uemail,:upass,:ulang)"); 
       $stmt->bindParam(":ufname", $fname); 
       $stmt->bindParam(":ulname", $lname); 
       $stmt->bindParam(":ucontact", $contactnum); 
       $stmt->bindParam(":uemail", $email); 
       $stmt->bindParam(":upass", $pass); 
       $stmt->bindParam(":ulang", $lang); 
       if($stmt->execute()) 
       { 
        echo "Successfully Added"; 
       } 
       else{ 
        echo "Query Problem"; 
       } 
      } 
      catch(PDOException $e){ 
       echo $e->getMessage(); 
      } 
     } else { 
      echo $email . ' already taken, try other email address'; 
     } 
    } else { 
     echo 'Email address is blank'; 
    } 
} 

?> 

Answer 2

您需要設置PDO錯誤模式。例如：

/* @var $dbConn PDO */ 
$dbConn = new PDO("mysql:host=$dbHost;dbname=$dbName", $dbUsername, $dbPassword); 
/* set the PDO error mode to exception */ 
$dbConn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);