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從來就得到了下面的SQL代碼來生成APEX樹:甲骨文的Apex樹三層以上
select 1 as status, 1 pid, 'Fehlermeldungen' as titel, null as icon, '1' as value, NULL as tooltip, NULL as link from dual
union
select -1 as status, 2 pid, k.kname as titel, NULL as icon, k.knr||'0' as value, NULL as tooltip, NULL as link from kunde k where
(select count(fmtext) from fehlermeldung f where f.knr = k.knr) > 0
union
select 0 as status, 3 pid, fmtext as titel, NULL as icon, k.knr||fmnr as value, NULL as tooltip, null as link from kunde k, fehlermeldung f where f.knr = k.knr
order by value
現在,我想添加一個第四層,但如果我試圖讓另一個工會當pid = 4時,條目附加到最後的選擇。 我該如何管理?