創建表和樣本數據:
SQL> create table t (a varchar2(20) not null
2 , b number(38) not null
3 , c number(38) not null
4 , d varchar2(20) not null);
Table created.
SQL> insert into t values ('A1', 2, 10, 'b');
1 row created.
SQL> insert into t values ('A2', 7, -9, 'bc');
1 row created.
SQL> insert into t values ('A3', 7, 12, 'fg');
1 row created.
SQL> insert into t values ('A1', 2, 20, 'sa');
1 row created.
SQL> insert into t values ('A2', 7, 4, 'sa');
1 row created.
SQL> commit;
Commit complete.
爲了幫助找出更新,創建一個查詢,給出了預期的效果,我的理解是:(解決方案的不一部分,只是一部分問題)
SQL> select t.a, t.b
2 , case when agg_t.min_c >= 0 then avg_c -- all values of c are >= 0
3 when agg_t.max_c < 0 then min_c -- all values of c are < 0
4 else agg_t.max_c end as c
5 , t.d
6 from (select a, b, min(c) as min_c
7 , max(c) as max_c , avg(c) as avg_c
8 from t
9 group by a, b) agg_t
10 inner join t on agg_t.a = t.a and agg_t.b = t.b
11/
A B C D
-------------------- ---------- ---------- --------------------
A3 7 12 fg
A1 2 15 sa
A2 7 4 bc
A2 7 4 sa
A1 2 15 b
使用merge
在更新過程中,使現有的agregate值:
SQL> merge into T dest
2 using (select a, b, min(c) as min_c
3 , max(c) as max_c , avg(c) as avg_c
4 from t
5 group by a, b) src
6 on (dest.a = src.a and dest.b = src.b)
7 when matched then update
8 set c = case when src.min_c >= 0 then avg_c -- all values of c are >= 0
9 when src.max_c < 0 then min_c -- all values of c are < 0
10 else src.max_c end
11/
5 rows merged.
SQL> select * from t;
A B C D
-------------------- ---------- ---------- --------------------
A1 2 15 b
A2 7 4 bc
A3 7 12 fg
A1 2 15 sa
A2 7 4 sa
回滾到最初的測試數據:
SQL> rollback;
Rollback complete.
這個查詢將不會更新,其中一個變化是不實際作出行,減少鎖定,撤消和重做:
SQL> merge into T dest
2 using (select a, b
3 , case when min_c >= 0 then avg_c -- all values of c are >= 0
4 when max_c < 0 then min_c -- all values of c are < 0
5 else max_c end as new_c
6 from (select a, b, min(c) as min_c
7 , max(c) as max_c , avg(c) as avg_c
8 from t
9 group by a, b)) src
10 on (dest.a = src.a and dest.b = src.b)
11 when matched then update set c = new_c
12 where c <> new_c
13 or (c is null and new_c is not null)
14 or (c is not null and new_c is null)
15/
3 rows merged.
SQL>
SQL> select * from t;
A B C D
-------------------- ---------- ---------- --------------------
A1 2 15 b
A2 7 4 bc
A3 7 12 fg
A1 2 15 sa
A2 7 4 sa
至少請嘗試使其更具可讀性。 – 2011-02-08 12:20:41