更新PHP的MySQL VAL + 5

Question

你能幫助我，請我whant更新我的表X點添加到值：

$Fr_Points = 5; 
$Fr_Descri = "Un avis a été donné"; 
$EN_PDO = $pdo->prepare("UPDATE ".$TB_USER_REPORT_STATS." SET Points = Points+".$Fr_Points.", Description=:Fr_Descri WHERE Pseudo='".$Fr_Pseudo."' "); 
$EN_PDO->bindParam(":Fr_Points",  $Fr_Points); 
$EN_PDO->bindParam(":Fr_Descri",  $Fr_Descri); 
$EN_PDO->execute(); 

但我得到一個錯誤：

Fatal error: Uncaught PDOException: SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens in /xxx/xxx/www/login/avis.php:61 Stack trace: #0 /xxx/xxx/www/login/avis.php(61): PDOStatement->execute() #1 {main} thrown in /xxx/xxx/www/login/avis.php on line 61 

燦你能幫我嗎？ Cordialy

Answer 1

你有準備的語句混合concatination：

$EN_PDO = $pdo->prepare("UPDATE ".$TB_USER_REPORT_STATS." SET Points = Points+:Fr_Points, Description=:Fr_Descri WHERE Pseudo=:Fr_Pseudo "); 

$EN_PDO->bindParam(":Fr_Points",  $Fr_Points); 
$EN_PDO->bindParam(":Fr_Descri",  $Fr_Descri); 
$EN_PDO->bindParam(":Fr_Pseudo",  $Fr_Pseudo); 
$EN_PDO->execute(); 

每個命名佔位符必須通過