複雜的SQL查詢

Question

我有以下的數據庫表（這簡單地說明問題）

CampaignTx

campaignTx_id | member_id | date_created | shop_id 
1 | 2 | 7/12/2009 | 2 
2 | 4 | 7/13/2009 | 3 
3 | 6 | 7/14/2009 | 4 
4 | 5 | 8/14/2009 | 3 
5 | 10| 8/19/2009 | 1 

可靠性

Reliability_id | campaignTx_id | status 
1 | 3 | 0 
2 | 2 | 1 
3 | 4 | 2 
4 | 5 | 3 
5 | 7 | 1 

店

Shop_id | Shop_name | City_id 
1 | shop 1| 5 
2 | shop 2| 7 
3 | shop 3| 7 
4 | shop 4| 6 

市

City_id | City_name 
5 | city 1 
6 | city 2 
7 | city 3 

我想在下表（每行由城市，年份和月份分組）：

City| year | month| num_of_campaignTx_records | num_of_reliability_records | num_of reliability_records with status = 0 |num_of reliability_records with status = 1| num_of reliability_records with status = 2| num_of reliability_records with status = 3 

我應該怎麼寫SQL查詢得到這個表？

我現在下面的查詢，但我不知道怎麼寫的最後4列：

select datepart(year,[Tx].date_created) as year, 
datepart(month,[Tx].date_created) as month, 
[city].nameTc as city, 
count([Tx].date_created) as 'total num of campaign Tx records', 
count([rel].CreateDate) as 'num of reliability records' 

from campaigntx as [Tx] 

full join [Reliability] as [rel] 
on [rel].[CampaignTx_id] = [Tx].[CampaignTx_id] 

join shop as [shop] 
on [Tx].shop_id = [shop].shop_id 

join City as [city] 
on [city].city_id = [shop].city_id 

group by datepart(year,[Tx].date_created),datepart(month,[Tx].date_created), [city].nameTc 

Answer 1

我沒有測試過，但在以下的說法應該工作

sum(when [rel].status = 1 then 1 else 0) as 'num of reliability records' 

Answer 2

看起來像是PIVOT的情況

WITH Qry AS (
select datepart(year,[Tx].date_created) as year, 
datepart(month,[Tx].date_created) as month, 
[city].nameTc as city, 
count([Tx].date_created) as 'total num of campaign Tx records', 
count([rel].CreateDate) as 'num of reliability records', 
[re].status 
from campaigntx as [Tx] 

full join [Reliability] as [rel] 
on [rel].[CampaignTx_id] = [Tx].[CampaignTx_id] 

join shop as [shop] 
on [Tx].shop_id = [shop].shop_id 

join City as [city] 
on [city].city_id = [shop].city_id 

group by datepart(year,[Tx].date_created),datepart(month,[Tx].date_created), [city].nameTc 
) 
SELECT year, month, city, [toal num of campaign Tx records], 
    [0] as [No status 0], [1] as [No status 1], [2] as [No status 2], ... 
FROM Qry 
PIVOT (SUM([number or reliability records]) FOR status in ([0],[1],[2],...)) AS PVT;