複雜的SQL SELECT查詢

表模式：複雜的SQL SELECT查詢

CREATE TABLE TRANSACTIONDETAILS 
(
    TransNo CHAR(15), 
    Serial INT, 
    Project CHAR(3) 
)

數據集：

+-----------------+--------+---------+ 
|  TransNo  | Serial | Project | 
+-----------------+--------+---------+ 
| A00000000000001 |  1 |  100 | 
| A00000000000001 |  2 |  101 | 
| A00000000000002 |  1 |  100 | 
| A00000000000002 |  2 |  101 | 
| A00000000000003 |  1 |  100 | 
| A00000000000003 |  2 |  200 | 
| A00000000000004 |  1 |  200 | 
| A00000000000004 |  2 |  100 | 
| A00000000000005 |  1 |  101 | 
| A00000000000005 |  2 |  100 | 
+-----------------+--------+---------+

我想，以確定這些交易有同一個項目組。

預期輸出：

+-----------------+--------+---------+---------+ 
|  TransNo  | Serial | Project | Flag | 
+-----------------+--------+---------+---------+ 
| A00000000000001 |  1 |  100 |  1 | 
| A00000000000001 |  2 |  101 |  1 | 
| A00000000000002 |  1 |  100 |  1 | 
| A00000000000002 |  2 |  101 |  1 | 
| A00000000000005 |  1 |  101 |  1 | 
| A00000000000005 |  2 |  100 |  1 | 
| A00000000000003 |  1 |  100 |  2 | 
| A00000000000003 |  2 |  200 |  2 | 
| A00000000000004 |  1 |  200 |  2 | 
| A00000000000004 |  2 |  100 |  2 | 
+-----------------+--------+---------+---------+

我使用SQL Server 2012及更高版本。

謝謝。

UPDATE 1：如果我從輸入數據集中獲得以下內容，我的部分目標就會實現。

+-----------------+---------+---------+ 
|  TransNo  | Project1| Project2| 
+-----------------+---------+---------+ 
| A00000000000001 |  100 |  101 | 
| A00000000000002 |  100 |  101 | 
| A00000000000003 |  100 |  200 | 
| A00000000000004 |  200 |  100 | 
| A00000000000005 |  101 |  100 | 
+-----------------+---------+---------+

更新2：

數據集

+-----------------+--------+---------+ 
|  TransNo  | Serial | Project | 
+-----------------+--------+---------+ 
| A00000000000001 |  1 |  100 | 
| A00000000000001 |  2 |  101 | 
| A00000000000001 |  3 |  200 | 
| A00000000000002 |  1 |  100 | 
| A00000000000002 |  2 |  101 | 
| A00000000000003 |  1 |  100 | 
| A00000000000003 |  2 |  200 | 
| A00000000000004 |  1 |  200 | 
| A00000000000004 |  2 |  100 | 
| A00000000000005 |  1 |  101 | 
| A00000000000005 |  2 |  100 | 
+-----------------+--------+---------+

輸出：

+-----------------+--------+---------+---------+ 
|  TransNo  | Serial | Project | Flag | 
+-----------------+--------+---------+---------+ 
| A00000000000001 |  1 |  100 |  1 | 
| A00000000000001 |  2 |  101 |  1 | 
| A00000000000001 |  2 |  200 |  1 | 
| A00000000000002 |  1 |  100 |  2 | 
| A00000000000002 |  2 |  101 |  2 | 
| A00000000000005 |  1 |  101 |  2 | 
| A00000000000005 |  2 |  100 |  2 | 
| A00000000000003 |  1 |  100 |  3 | 
| A00000000000003 |  2 |  200 |  3 | 
| A00000000000004 |  1 |  200 |  3 | 
| A00000000000004 |  2 |  100 |  3 | 
+-----------------+--------+---------+---------+

來源

2015-12-29 Esty

什麼是'Flag'列邏輯？ – Fabio

標誌只是識別具有相同項目集的事務。那些在項目100和101之間承諾的事務被標記爲1，那些100和200被標記爲2.它可以是任何int，char只是一個標識節點。 – Esty

嘗試此

;WITH cte 
    AS (SELECT *, 
       Concat(Min(Project)OVER(partition BY TransNo), Max(Project)OVER(partition BY TransNo)) AS inter 
     FROM TRANSACTIONDETAILS) 
SELECT TransNo, 
     Serial, 
     Project, 
     Dense_rank()OVER(ORDER BY inter) AS flag 
FROM cte

SQL FIDDLE DEMO

更新：對於部分結果

SELECT TransNo, 
     Max(CASE WHEN Serial = 1 THEN Project END) AS Project_1, 
     Max(CASE WHEN Serial = 2 THEN Project END) AS Project_2 
FROM TRANSACTIONDETAILS 
GROUP BY TransNo

來源

2015-12-29 04:47:22

你只是搖滾... – Esty

請你看看更新2.如果在交易中存在3個項目會怎樣。通過獲取交易A00000000000001的最小和最大限制，其100200作爲交易。有什麼辦法可以讓它變成100101200？ – Esty

@TanjimRahman - 可以請問這是一個新的問題 –

CREATE TABLE #test_trans 
    ([TransNo] varchar(15), [Serial] int, [Project] int) 
; 

INSERT INTO #test_trans 
    ([TransNo], [Serial], [Project]) 
VALUES 
    ('A00000000000001', 1, 100), 
    ('A00000000000001', 2, 101), 
    ('A00000000000001', 3, 200), 
    ('A00000000000002', 1, 100), 
    ('A00000000000002', 2, 101), 
    ('A00000000000003', 1, 100), 
    ('A00000000000003', 2, 200), 
    ('A00000000000004', 1, 200), 
    ('A00000000000004', 2, 100), 
    ('A00000000000005', 1, 101), 
    ('A00000000000005', 2, 100) 
; 

[![;WITH cte 
    AS (select \[TransNo\],(
Select cast(ST1.\[Project\] as varchar(max)) AS \[text()\] 
       From #test_trans ST1 
       where st1.TransNo=st2.TransNo 
       For XML PATH ('')) as rn,Project,st2.Serial from #test_trans st2) 
SELECT TransNo, 
     Serial, 
     Project, 
     Dense_rank()OVER(ORDER BY rn) AS flag 
FROM cte][1]][1]

來源

2015-12-29 07:14:39 Smart003

複雜的SQL SELECT查詢

回答

相關問題