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我想在一個位置上畫一個矩形給我的手指觸摸屏幕,但是當我點擊按鈕繪製時,矩形的位置是錯誤的,對於很多像素在右邊和上面。我發佈了代碼和我的xml佈局文件,同時給出了此觸摸事件的「觸摸事件」和「矩形位置」的圖像,它是ADV模擬器上我的imageView的捕獲圖像。Android正在繪製錯誤的位置imageView
OnTouch事件:
public boolean onTouch(View view, MotionEvent event) {
switch (event.getAction())
{
case MotionEvent.ACTION_UP:
{
x = event.getX();
y = event.getY();
/*int[] img_coordinates = new int[2];
imageView.getLocationOnScreen(img_coordinates);
Toast.makeText(getApplicationContext(), String.valueOf(img_coordinates[0]) + " " + String.valueOf(img_coordinates[1]), Toast.LENGTH_LONG).show();
x = x - img_coordinates[0];
y = y - img_coordinates[1];*/
Toast.makeText(getApplicationContext(), String.valueOf(x) + " " + String.valueOf(y), Toast.LENGTH_LONG).show();
imageView.invalidate();
break;
}
case MotionEvent.ACTION_MOVE:
{
if (event.getHistorySize() == 0)
{
x = event.getX();
y = event.getY();
}
if (x == 0 && y == 0)
{
x = event.getX();
y = event.getY();
}
canvas.drawLine(x, y, event.getX(), event.getY(), paint);
x = event.getX();
y = event.getY();
imageView.invalidate();
}
}
return true;
}
事件繪圖:
public void btnMove_Click(View view)
{
if(orientation == "UP")
{
canvas.drawLine(x, y, x, y - pixelFoot, paint);
Toast.makeText(getApplicationContext(), "Dibujado en " + String.valueOf(x) + " " + String.valueOf(y), Toast.LENGTH_LONG).show();
y -= pixelFoot;
imageView.invalidate();
}
else if(orientation == "DOWN")
{
canvas.drawLine(x, y, x, y + pixelFoot, paint);
Toast.makeText(getApplicationContext(), "Dibujado en " + String.valueOf(x) + " " + String.valueOf(y), Toast.LENGTH_LONG).show();
y += pixelFoot;
imageView.invalidate();
}
else if(orientation == "LEFT")
{
canvas.drawLine(x, y, x - pixelFoot, y, paint);
Toast.makeText(getApplicationContext(), "Dibujado en " + String.valueOf(x) + " " + String.valueOf(y), Toast.LENGTH_LONG).show();
x -= pixelFoot;
imageView.invalidate();
}
else if(orientation == "RIGHT")
{
canvas.drawLine(x, y, x + pixelFoot, y, paint);
Toast.makeText(getApplicationContext(), "Dibujado en " + String.valueOf(x) + " " + String.valueOf(y), Toast.LENGTH_LONG).show();
x += pixelFoot;
imageView.invalidate();
}
}
XML佈局文件:我的屏幕
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".MainActivity" >
<ImageView
android:id="@+id/imgFingerPaint"
android:layout_width="800px"
android:layout_height="564px"
android:layout_alignParentLeft="true"
android:layout_alignParentTop="true"
android:layout_toLeftOf="@+id/Button01"
android:src="@drawable/edittext_rounded_corners" />
<Button
android:id="@+id/btnMove"
android:layout_width="90px"
android:layout_height="90px"
android:layout_alignParentBottom="true"
android:layout_alignTop="@+id/btnRight"
android:layout_toRightOf="@+id/btnRight"
android:background="@drawable/edittext_rounded_corners"
android:onClick="btnMove_Click"
android:text="PASO" />
</RelativeLayout>
圖片時,我做了一些觸摸事件和一些抽獎活動:
您的手機對於給定圖像的方向是什麼?另外,什麼是pixelFoot&它來自哪裏? –
不要責怪你的錯誤的機器人:它你在錯誤的位置 – pskink
@dev_feed方向是'風景',pixelFoot是一個變量,我從另一個活動接收並獲得一個步幅的像素距離。 – Imrik